Solve for the variable. Show all work. |2x

Seamstress Jane has purchased 50 yards of red fabric and 110 yards of gold fabric to make red and gold curtains. What is the lar

Alisiya [41]

Answer: There are 10 largest number of curtains she can make if she wants all the curtains to be exactly the same length.

There are 5 red fabrics and 11 gold fabrics that would be used for each curtain.

Step-by-step explanation:

Since we have given that

Number of yards of red fabric purchased by Jane = 50

Number of yards of gold fabric purchased by Jane = 110

We need to find the largest number of curtains she can make if she wants all the curtains to be exactly the same length.

For this we will find H.C.F. of 50 and 110.

Factors of 50 = 1, 2, 5, 10, 25, 50.

Factors of 110 = 1, 2, 5, 10, 11, 22, 55, 110.

So, Highest common factor of 50 and 110 is 10.

So, there are 10 largest number of curtains she can make if she wants all the curtains to be exactly the same length.

Number of yards of red fabric is given by

$\frac{50}{10}=5$

Number of yards of gold fabric is given by

$\frac{110}{10}=11$

Hence, there are 5 red fabrics and 11 gold fabrics that would be used for each curtain.

4 0

3 years ago

1. The data given below includes data from 42 candies, and 7 of them are red. The company that makes the candy claims that 33%

jeyben [28]

Answer:

The 95% confidence interval for true proportion of red candies is (5%, 27%).

The true proportion of red candies made by the company is different from 33%.

Step-by-step explanation:

The hypothesis to determine whether the claim made by the candy company is correct or not is:

H₀: The true proportion of red candies made by the company is 33%, i.e. p = 0.33.

Hₐ: The true proportion of red candies made by the company is different from 33%, i.e. p ≠ 0.33.

A (1 - α)% confidence interval can be constructed to check this claim.

The decision rule is:

If the confidence interval consists the null value then the null hypothesis will not be rejected. Otherwise it will be rejected.

The (1 - α)% confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The information provided is:

n = 42

X = number of red candies = 7

Compute the sample proportion of candies that are red as follows:

$\hat p=\frac{X}{n}=\frac{7}{42}=0.167$

The critical value of z for 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use a z-table for the critical value.

Compute the 95% confidence interval for true proportion of red candies as follows:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.167\pm 1.96\times \sqrt{\frac{0.167(1-0.167)}{42}}\\=0.16\pm0.1137\\=(0.0463, 0.2737)\\\approx(0.05, 0.27)$

The 95% confidence interval for true proportion of red candies is (5%, 27%).

The confidence interval does not contains the null value.

Thus, the null hypothesis will be rejected at 5% level of significance.

Conclusion:

The true proportion of red candies made by the company is different from 33%.

7 0

3 years ago

Find the solution to the systems of equations using the elimination method.

vredina [299]

X=-2/3y+11/3

x=-3/5y+14/5

5 0

2 years ago

Read 2 more answers

Which choice is a graph of the solution set for 12 - X < 8? Pleaseeeee helpppppp NUMBER 14

yarga [219]

Answer:

B

Hope this helps!

explanation:

we solve the inequality and to do that we must first subtract 12 from both sides, which gets us -x<-4, then we divide both sides by -1, which gives us x>4, since we have to flip the sign when we divide by a negative. when we graph this, there will be a circle around 4 and the arrow pointing to the right, since it's greater than.

7 0

3 years ago

In the division problem, 0.08 ÷ 2 = 0.04, the_____ is 0.08

-Dominant- [34]

In the division problem, 0.08 ÷ 2 = 0.04, the dividend is 0.08.

4 0

2 years ago

Read 2 more answers

Solve for the variable. Show all work. |2x - 3| = 15