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liq [111]
2 years ago
11

Your cat’s vet recommends a diet for your cat of no more than 1,800 calories per week. In a 7-day week, how many daily calories

you can feed your cat and still be following the vet’s recommendation?
Mathematics
1 answer:
lisov135 [29]2 years ago
4 0
The average indoor cat should have 20 calories per pound to maintain weight. The average outdoor only cat should have 35 calories per pound to maintain weight. Indoor/outdoor cats are somewhere in between. o If your indoor cat weighs 10 pounds, then they should be eating approximately 200 calories per day.
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Complete the equation. (x-2)(x^2 + 2x + 4) = ( , )
yanalaym [24]

Answer:

Step-by-step explanation:

x(x² + 2x + 4)-2((x² + 2x + 4)

x³+2x²+4x -2x²-4x-8

x³-8

6 0
2 years ago
Suppose a certain drug test is 85% accurate, meaning that if a person is a user, the result is positive 85% of the time, and if
kakasveta [241]

Answer:

29.411 %  of the result is true.

Step-by-step explanation:

This test's sensitivity is low.

Suppose we have 5 drug users and 85% of the test is accurate meaning that 5* 0.85= 4.25 people are drug users which is true.

But if work for the non users than 5% people being drug users means 95 people are non drug users out of the hundred.

And 85 % accuracy would give  95* 0.85= 80.75 which is very high.

And out of the 80.75 * 15%= 12.11 only 12 are positive .

The results give us  5 out of 17  true possibilities

or 5/17 *100= 29.411 %  of the result is true.

8 0
3 years ago
The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.
Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

(c) 0

Step-by-step explanation:

Let <em>X</em> denote the heights of women in the USA.

It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

8 0
3 years ago
What is the sum of 4m(m-6) and 8(m-4)?
Alik [6]

Step-by-step explanation:

4m2 - 24m + 8m - 32

4m2 - 16m - 32

7 0
3 years ago
Please help!!! Fast
tatyana61 [14]
2x + 5y = 4
5y = -2x + 4
  y = -2/5 x + 4/5
parallel lines have same slope so slope = -2/5

equation
y +4 = -2/5 (x - 5)
y = -2/5 x + 2 - 4
y = -2/5 x - 2

answer is D
y = -2/5 x - 2
3 0
3 years ago
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