From $2003$ onward, the number of daily visitors to a website increased by $200\%$ every two years. So, for example, the number
of visitors in $2011$ was $200\%$ more than the number of visitors in $2009$. In what year was the number of daily visitors $800\%$ more than the number of daily visitors in $2003$? Explain, in words, why your answer is correct.
If the number of visitors was, say, 100 people in 2003, then in 2005 that number would have gone up to 300 people, which is a 200% increase. And that number would have gone up to 900 people in 2007, which is an 800% increase.
For this case we have the following inequations: 1.5x-1> 6.5 7x + 3 <-25 Clearing x from each one we have: For 1.5x-1> 6.5: 1.5x> 6.5 + 1 1.5x> 7.5 x> 7.5 / 1.5 x> 5 For 7x + 3 <-25: 7x <-25-3 7x <-28 x <-28/7 x <-4 The solution set is: (inf, -4) U (5, inf) Answer: See attached image