1) c) y = 500 * 2^x
In year 1, x = 1 and the population is 500 * 2^1 = 1000
In year 2, this doubles to 500 * 2^2 = 500 * 4 = 2000
ans so on
This model describes the population doubling every year
2)
A) 3 (1/2)^x and C) (0.25)^x
These numbers reduce as x increases because there is a number with an absolute value less than 1 is being raised to the power of x. They also will never totally reach zero or become negative, but will approach zero as x becomes very large.
The straight line ON has the following equation :
(x - 18)/(x - 0) = (y - 12)/(y - 0)
Where (18,12) are coordinates of N and (0,0) are coordinates of O.
x - 18/x = y - 12/y
-18y = - 12x
y =12x/18 - - - - - (a)
The coordinates satisfy equation (a) are (7.5, 5)
Therefore D is the correct answer.
Good luck
The first thing we must do for this case is to find the surface area of the rectangular prism.
We have then:
A = 2 * (l * h) + 2 * (h * w) + 2 * (w * l)
Where,
w: width
l: long
h: height
Substituting values we have:
A = 2 * (10 * 8) + 2 * (8 * 8) + 2 * (8 * 10)
A = 448 in ^ 2
Answer:
the least amount of wrapping paper needed to wrap the gift box answer is:
A = 448 in ^ 2
-7.08 as a fraction in simplest form would be -177/25
Area of sandbox = 169 square feet
Area of square with side 'x' is given by the formula = 
We have to determine the total length of wood Drew needs to make the sides of the sandbox.
Total length of wood required would be equal to perimeter of sandbox.
Let 'a' be the side of the square sandbox.
So, Area of sandbox = 169
a = 13 feet
Total length of wood required to make sides of the sandbox = Perimeter of the square sandbox = 
= 
= 52 feet.
Therefore, 52 feet of wood is required to make the sides of the square sandbox.
