Answer:
The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.
Step-by-step explanation:
The mean sample of the sum of n random variables is

If
are indentically distributed and independent, like in the situation of the problem, then the variance of
will be the sum of the variances, in other words, it will be n times the variance of
.
However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus
and as a result, the standard deviation of
is the standard deviation of
divided by
.
Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:
- Restaurants: We have boxes with 9 salmon each, so it will be

- Grocery stores: Each carton has 49 salmon, thus the standard deviation is

- Discount outlet stores: Each pallet has 64 salmon, as a result, the standard deviation is

We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.
Answer:
5.00
Step-by-step explanation:
the price for 3 avacados is 3.00 because 6 are 10 if you divide 10 by 2 you get 5
Answer:
1 hour and 45 minutes
and 1 hour
Step-by-step explanation:
x= run
y= walk
5x+2.5y = distance
5x+2.5(1.5)=12.5
solve for x
5x=8.75
x=1.75
1.75 in hours is 1 hour and (60*.75)=45
1 hour and 45 minutes
" If the marathon race participant ran for 2 hours, how many hours did the participant walk?"
We use the same equation
5x+2.5y=distance
we'll assume that they till walked 12.5 miles
which means that
5(2)+2.5y=12.5
solve for y
2.5=2.5y
y=1
1 hour
Answer:
D would be the answer
Step-by-step explanation:
Took the test got it correct <33 good luck
x = –6
Solution:
Given expression is
.
Step 1: Isolate the radical by subtracting 5 from both sides of the equation.
![\Rightarrow\sqrt[3]{x-2}+5-5=3-5](https://tex.z-dn.net/?f=%5CRightarrow%5Csqrt%5B3%5D%7Bx-2%7D%2B5-5%3D3-5)
![\Rightarrow\sqrt[3]{x-2}=-2](https://tex.z-dn.net/?f=%5CRightarrow%5Csqrt%5B3%5D%7Bx-2%7D%3D-2)
Step 2: Cube both sides of the equation to remove the cube root.
![\Rightarrow(\sqrt[3]{x-2})^3=(-2)^3](https://tex.z-dn.net/?f=%5CRightarrow%28%5Csqrt%5B3%5D%7Bx-2%7D%29%5E3%3D%28-2%29%5E3)
Cube and cube root get canceled in left side of the equation.

Step 3: To solve for x.
Add 2 on both sides of the equation.


Hence the solution is x = –6.