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lana [24]
4 years ago
15

Please help me with this math question

Mathematics
1 answer:
Dafna11 [192]4 years ago
4 0

Answer:

Step-by-step expla5+7x12+75-94x347+7 2/9​nation:

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Help me ASAP with this problem
Jobisdone [24]

Answer:

114cm

Step-by-step explanation:

3×8×4=96

3×3×2=18

96+18=114

3 0
3 years ago
What must be true of two rational expressions before they can be added
Kisachek [45]

Answer:

reeee

Step-by-step explanation:

4 0
3 years ago
The graph shows the relationship between time
musickatia [10]

Answer:

The machine can make 24 bottles of soda per minute

Step-by-step explanation:

Looking at the graph of the relationship, we can see that the number of bottles per minute simply represent the slope of the line

Thus, by calculating the slope using the given points, we can have the number of bottles per minute

We have the formula as;

m = (y2-y1)/(x2-x1)

(x1,y1) = (4,96)

(x2,y2) = (6,144)

m = (144-96)/(6-4) = 48/2 = 24

8 0
3 years ago
A regular hexagon is inscribed in a circle and another regular hexagon is circumscribed about the same circle. What is the ratio
Anna007 [38]

4/3 of the area of the larger hexagon to the area of the smaller hexagon

Let the sides of the interior hexagon be 2 cm long, then this hexagon is made up of 6 equilateral triangles of side = 2.

The area of this hexagon = 6 * 1 * sqrt3 = 6 sqrt3 ( as the triangle is made up of 2 60-30-90 triangles)

The exterior hexagon is made up of 6 equilateral triangles with altitude 2 and the area = 6 * 2 * (2 / sqrt3 ) = 24 / sqrt3

area exterior hex / interior hex = 24 / sqrt3 * 1 / 6sqrt3 = 24/18

= 4/3

Required ratio = 4/3 answer

Learn more about Equations:

brainly.com/question/16450098

#SPJ4

3 0
2 years ago
In an experiment to measure the lifetimes of parts manufactured from a certain aluminum alloy, 73 parts were loaded cyclically u
kari74 [83]

Answer:

0.0094.

Step-by-step explanation:

For the given experiment, let X be the lifetimes of parts manufactured from a certain aluminum alloy.

sample size =73

Sample mean = 784

Sample standard deviation = 120

Let µ represent the mean number of kilocycles to failure for parts of this type.

Null hypothesis, H0 : µ ≤ 750

Alternative hypothesis, H1 : µ > 750.

z=\dfrac{\overline{X}-\mu}{\frac{s}{\sqrt{n}}}

where,

\overline{X} is sample mean.

\mu is population mean.

s is sample standard deviation.

n is the sample size.

z=\dfrac{783-750}{\frac{120}{\sqrt{73}}}

z=2.35

It is a right tailed test because alternative hypothesis is µ > 750. So, P-value is the probability of observing a sample mean greater that 783 or the probability of P(z>2.35).

P=P(z>2.35)

P=1-P(z

P=1-0.9906

P=0.0094

Therefore the P-value is 0.0094.

5 0
3 years ago
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