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4 years ago

How to solve c+3/4=5/4?

Mathematics

2 answers:

kotegsom [21]4 years ago

8 0

If you are solving for c:

c + 3/4 = 5/4

5/4 - 3/4 = c

c = 2/4 or 1/2

Lena [83]4 years ago

7 0

Farfaefeafeavdavdaveaveava

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Without solving the systems, explain why the following systems must have the same solution.

8_murik_8 [283]

Answer:

Both system of equations are intersecting

Step-by-step explanation:

The equations are of the form

ax+by+c=0

Two equations have no solution when

$\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}$

i) 4x−5y-13=0

3x+6y-11=0

$\frac{4}{3}\neq \frac{5}{6}\neq \frac{13}{11}$

So, they are intersecting lines and do have the same solution.

ii) 8x−10y-26=0

x−11y-2=0

$\frac{8}{1}\neq \frac{-10}{-11}\neq \frac{13}{11}$

So, they are intersecting lines and do have the same solution.

6 0

3 years ago

The origin is a point anywhere along the x-axis. True or False

a_sh-v [17]

Answer:

False

Step-by-step explanation:

The origin is at 0 on the x-axis, and 0 on the y-axis. Hence, (0,0) lies on both the axis.

hope this helps and is right. p.s. i really need brainliest :)

if my answer is wrong then i am incredibly sorry!

5 0

3 years ago

If (54)m = 51^2, what is the value of m?

Alla [95]

M= 48.16666666666667. You can verify by multiplying it by 54, and comparing it with 51x51 and see if you get same results.

7 0

4 years ago

Help Part A pArt B 6th grade math

VLD [36.1K]

Answer:

Kinda making me dizzy look sideways haha. Okay so for A. 6 books. For B i'm not sure.. let's see what I get in a moment.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Is my answer correct? 10 points + brainleist!

Liono4ka [1.6K]

Answer:

your answer is incorrect. The correct answer is $h=-13$ and $k=13$ .

Step-by-step explanation:

If a quadratic function is $f(x)=ax^2+bx+c$ and a>0, then minimum value of the function at point $\left(-\dfrac{b}{2a},f(-\dfrac{b}{2a})\right)$ .

The given function is

$f(x)=x^2+bx+182$

Here, a=1, b=b and c=182. So.

$-\dfrac{b}{2a}=-\dfrac{b}{2(1)}=-\dfrac{b}{2}$

Put $x=-\dfrac{b}{2}$ in the given function to find the minimum value of the function.

$f(-\dfrac{b}{2})=(-\dfrac{b}{2})^2+b(-\dfrac{b}{2})+182$

We know that minimum value is 13. So,

$13=\dfrac{b^2}{4}-\dfrac{b^2}{2}+182$

$13-182=-\dfrac{b^2}{4}$

$-169=-\dfrac{b^2}{4}$

$169\times 4=b^2$

Taking square root on both sides.

$13\times 2=b$

$b=26$

The value of b is 26.

So, the given function is

$f(x)=x^2+26x+182$

Now, add and subtract square of half of coefficient of x.

$f(x)=x^2+26x+182+(13)^2-(13)^2$

$f(x)=(x^2+2(13)x+(13)^2)+182-169$

$f(x)=(x+13)^2+13$

On comparing with $f(x)=(x-h)^2+k$ , we get

$h=-13$

$k=13$

Therefore, your answer is incorrect.

8 0

3 years ago