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Rainbow [258]
2 years ago
14

A regular hexagon is inscribed in a circle and another regular hexagon is circumscribed about the same circle. What is the ratio

of the area of the larger hexagon to the area of the smaller hexagon
Mathematics
1 answer:
Anna007 [38]2 years ago
3 0

4/3 of the area of the larger hexagon to the area of the smaller hexagon

Let the sides of the interior hexagon be 2 cm long, then this hexagon is made up of 6 equilateral triangles of side = 2.

The area of this hexagon = 6 * 1 * sqrt3 = 6 sqrt3 ( as the triangle is made up of 2 60-30-90 triangles)

The exterior hexagon is made up of 6 equilateral triangles with altitude 2 and the area = 6 * 2 * (2 / sqrt3 ) = 24 / sqrt3

area exterior hex / interior hex = 24 / sqrt3 * 1 / 6sqrt3 = 24/18

= 4/3

Required ratio = 4/3 answer

Learn more about Equations:

brainly.com/question/16450098

#SPJ4

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How to Simplify. (–21 × 3) + (15 ÷ –3)
vladimir2022 [97]

Answer:

-68 is your answer

Step-by-step explanation:

Remember to follow PEMDAS (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction)

First, solve each parenthesis

(-21 x 3) = -63

(15/-3) = -5

Next, add

(-63) + (-5) = -63 - 5 = -68

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5 0
3 years ago
Multiply the polynomials.<br> (4x- + 4x + 6)(7x + 5)
SashulF [63]

\implies {\blue {\boxed {\boxed {\purple {\sf {   \: 28 {x}^{3}  + 48 {x}^{2}  + 62x + 30}}}}}}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

(4 {x}^{2}  +  4x + 6)(7x + 5)

= \: 7x(4 {x}^{2}  + 4x + 6) + 5(4 {x}^{2}  + 4x + 6)

=  \: 28 {x}^{3}  + 28 {x}^{2}  + 42x + 20 {x}^{2}  + 20x + 30

Combining like terms, we have

=  \: 28 {x}^{3}  + (28 {x}^{2}  + 20 {x}^{2} ) + (42x + 20x) + 30

=  \: 28 {x}^{3}  + 48 {x}^{2}  + 62x + 30

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

3 0
3 years ago
Anyone know how to do these?
erastovalidia [21]

Answer:

B. 1/m¹⁸

Step-by-step explanation:

To simplify the equation, we start with the values inside the brackets.

Therefore  m⁻¹m⁵ results to m⁴.

This is because the sign between the m⁻¹ and m⁵ is multiplication, and when multiplying figures that have a similar base, we add the indices.

that is, -1+5=4

then we divide m⁴ by m⁻², that is, m⁴/m⁻²=m⁶

To divide figures that have the same base we subtract the powers.

That is, 4-(-2)=6

the resulting expression from inside the brackets will be (m⁶)³ which results to m⁻¹⁸ which is the same as 1/m¹⁸

3 0
3 years ago
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