Answer:
Step-bThis is an interesting problem. To solve it I should find two irrational numbers r and s such that rs is rational.
I am not sure I am able to do that. However, I am confident that the following argument does solve the problem.
As we know, √2 is irrational. In particular, √2 is real and also positive. Then √2√2 is also real. Which means that it is either rational or irrational.
If it's rational, the problem is solved with r = √2 and s = √2.
Assume √2√2 is irrational. Let r = √2√2 and s = √2. Then rs = (√2√2)√2 = √2√22 = √22 = 2. Which is clearly rational.
Either way, we have a pair of irrational numbers r and s such that rs is rational. Or do we? If we do, which is that?
(There's an interesting related problem.)
Chris Reineke came up with an additional example. This one is more direct and constructive. Both log(4) and √10 are irrational. However
√10 log(4) = 10log(2) = 2.y-step explanation:
Answer:
B. 31°; 106° and 43°.
Step-by-step explanation:
1) the rule is:
(5x-7)+(3x+1)+(11x-4)=180°;
2) if to solve this equation, then x=10°;
3) if x=10, then after the substitution the answer is 43;31;106.
Answer:
-11°C
Step-by-step explanation:
Original Temp = -2°C
Temp Drop (i.e temperature is reduced by) = 9°C
Final Temperature,
= Original Temp - Temp Drop
= -2°C - 9°C
= -11°C (Ans)
Answer:
10
Step-by-step explanation:
By using intersecting chord theorem:
NH.HT=MH.HY
(x+20)*8=12*20
x+20=12*20/8
x+20=240/8
x+20=30
x=30-20
x=10
I hope this helps you
length =width +6
Area=width × length
Area=w. (w+6)
