All categories

3 years ago

Henry paid for his lunch and wrote this equation to represent the change he got back from the cashier.

Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

8 0

C. is most likely the correct answer

You might be interested in

Factor the expression and simplify as much as possible. 24x(x2 1)4(x3 1)5 42x2(x2 1)5(x3 1)4

zmey [24]

Answer: 120[4(x^6 + x^3 + x^4 + x) +7(x^7 + x^4 + x^5 + x^2)]

Step-by-step explanation:

=24x(x^2 + 1)4(x^3 + 1)5 + 42x^2(x^2 + 1)5(x^3 + 1)4

Remove the brackets first

=[(24x^3 +24x)(4x^3 + 4)]5 + [(42x^4 +42x^2)(5x^3 + 5)4]

=[(96x^6 + 96x^3 +96x^4 + 96x)5] + [(210x^7 + 210x^4 + 210x^5 + 210x^2)4]

=(480x^6 + 480x^3 + 480x^4 + 480x) + (840x^7 + 840x^4 + 840x^5 + 840x^2)

Then the common:

=[480(x^6 + x^3 + x^4 + x) + 840(x^7 + x^4 + x^5 + x^2)]

=120[4(x^6 + x^3 + x^4 + x) +7(x^7 + x^4 + x^5 + x^2)]

6 0

3 years ago

How many solutions will the following system of linear equations have? –2x + 4y = –7 y= -1/2x + 5 A. 0 B. 1 C. 2 D. infinite

FinnZ [79.3K]

Answer:

B. 1

Step-by-step explanation:

they only cross at one point... look below

7 0

2 years ago

Read 2 more answers

Let f(x)=-2-7 and g(x)= -4x+6. Find (f*g)(-5)

Masja [62]

If (-5) = x then the anwser should be
-234

5 0

3 years ago

How much would $300 invested at 7% interest compounded continuously be worth after 4 years

marissa [1.9K]

The formula of compound continuously is
A=p e^rt
A future value?
P present value 300
R interest rate 0.07
T 4 years
E constant
A=300×e^(0.07×4)
A=396.94 round your answer to get
A=397

8 0

3 years ago

Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En

Sergio [31]

Answer:

$\bold{cot(t) =\dfrac{12}{5}}$

Step-by-step explanation:

Given that:

$Cosec (t) = -\frac{13}5$

for $\pi < t < \frac{3 \pi}2$

That means, angle $t$ is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

$cosec^2\theta -cot^2\theta =1$

here, $\theta =t$

So, $cosec^2t-cot^2t=1$

$\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}$

But, angle $t$ is in 3rd quadrant, so value of

$\bold{cot(t) =\dfrac{12}{5}}$

4 0

3 years ago