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Ratling [72]
3 years ago
8

(10-6) to the 3rd power *4 tothe 2nd power + (10 +2) to the 2nd power. Whats the answer?

Mathematics
2 answers:
andrew-mc [135]3 years ago
6 0
(10 - 6)^3 * 4^2 + (10 + 2)^2
4^3 * 4^2 + 12^2
4^5 + 12^2
1024 + 144
1168 <==
pantera1 [17]3 years ago
3 0
(10-6)3.42 + (12)2  64 .16+144 64   .   160 10240
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Can someone help me out on this please &lt;3 I have been stuck on this all day.​
ale4655 [162]

I believe the answers to your question should be as follow:

-4, 3

4, 3

-4, -3

-8, 6

Please tell me if this isn't correct!

8 0
3 years ago
HELPP ASAP
elena55 [62]

Answer:

(4, -5)

(3, -2)

7 0
3 years ago
Factoring a quadratic with leading coefficient greater than 1 <br><br> 3n^2+5n+2=0
Alika [10]

The algebraic factor is the multiplication term that can be common to the whole equation thus the factorization form of 3n²+5n+2=0 will be (n + 1)(3n + 2) = 0.

<h3>What is an algebraic factor?</h3>

An algebraic factor is the multiplication of two algebraic terms.

The root of the quadratic equation formed by the algebraic factor is always real.

That term could be in form of summation multiplication or in subtraction.

As per the given quadratic equation,

3n²+5n+2=0

Let's 5n = 2n + 3n

3n²+ (3n + 2n) + 2 = 0

3n² + 3n + 2n + 2 = 0

(3n² + 3n) + (2n + 2) = 0

3n(n + 1) + 2(n + 1) = 0

(n + 1 )(3n + 2) = 0

Hence "The algebraic factor is the multiplication term that can be common to the whole equation thus the factorization form of 3n²+5n+2=0 will be (n + 1)(3n + 2) = 0".

For more about the algebraic factor,

brainly.com/question/19426180

#SPJ1

8 0
1 year ago
Simplify <br>5(1-2x)-4(4-x)
____ [38]
The answer for this question is -6x-11
4 0
4 years ago
9x+3y-4z=37<br>4x+3y +7z =16<br>x-5y +8z=-31​
Evgen [1.6K]

Answer:

x = 2 , y = 5 , z = -1

Step-by-step explanation:

Solve the following system:

{9 x + 3 y - 4 z = 37 | (equation 1)

4 x + 3 y + 7 z = 16 | (equation 2)

x - 5 y + 8 z = -31 | (equation 3)

Subtract 4/9 × (equation 1) from equation 2:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+(5 y)/3 + (79 z)/9 = -4/9 | (equation 2)

x - 5 y + 8 z = -31 | (equation 3)

Multiply equation 2 by 9:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

x - 5 y + 8 z = -31 | (equation 3)

Subtract 1/9 × (equation 1) from equation 3:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x - (16 y)/3 + (76 z)/9 = -316/9 | (equation 3)

Multiply equation 3 by 9/4:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x - 12 y + 19 z = -79 | (equation 3)

Add 4/5 × (equation 2) to equation 3:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x+0 y+(411 z)/5 = -411/5 | (equation 3)

Multiply equation 3 by 5/411:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Subtract 79 × (equation 3) from equation 2:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y+0 z = 75 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Divide equation 2 by 15:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Subtract 3 × (equation 2) from equation 1:

{9 x + 0 y - 4 z = 22 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Add 4 × (equation 3) to equation 1:

{9 x+0 y+0 z = 18 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Divide equation 1 by 9:

{x+0 y+0 z = 2 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Collect results:

Answer:  {x = 2 , y = 5 , z = -1

4 0
3 years ago
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