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lorasvet [3.4K]
4 years ago
10

Would this be correct?

Mathematics
1 answer:
Dafna11 [192]4 years ago
8 0
No it would not just like what he said ^^^
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> Next question Get a similar question You this question below Find the distance between the points (-3,-3) and (-5,-1) Dista
dolphi86 [110]

Answer:

The answer is the square root of 8, or 2root2.

Step-by-step explanation:

Use the distance formula.

d = sqrt((-3-(-5))^2 + (-3-(-1)))

d = sqrt(2^2 + 2^2)

d = sqrt(4 + 4)

d = sqrt8

d = sqrt4 * sqrt2

d = 2 * sqrt2

8 0
3 years ago
an electrical charges $25 to make a house call plus $40 for every hour of work which equation shows how to find the total cost o
weeeeeb [17]
$25+$40 x number of hours worked.
For example, if he worked 3 hours it would cost $25+$40 x 3hrs= $145
3 0
3 years ago
5-64 =<br> A. -8<br> B. -4<br> C. 4 or -4<br> O D. -16
Alex787 [66]
The answer is -59 , you have the wrong answer choices
3 0
3 years ago
Find the value of X<br>I don't know how to solve for when the X are squared
Karolina [17]

we could look at the picture with a bit less lines, check the picture below.

that simply means that those two blue angles are linear angles and therefore add up to 180°.


\bf (x^2-6x+83)+(106)=180\implies x^2-6x+189=180 \\\\\\ x^2-6x+9=0~~~~ \begin{cases} (-3)(-3)=\stackrel{constant}{9}\\[0.8em] -3-3=\stackrel{\stackrel{\textit{middle~term}}{coefficient}}{-6} \end{cases}\implies (x-3)(x-3)=0 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill x=3~\hfill

3 0
3 years ago
For whole numbers between 1 and 1001, inclusive, let m be the sum of odd numbers and n be the sum of even numbers. What is the v
Svetradugi [14.3K]

Answer:

m - n = 501

Step-by-step explanation:

Remark

The first thing you have to do is find the number of odd and even numbers. This is where you have to be careful because there is a danger of being out by one.

equation

l = a + (n - 1)*d

Solution even

l = 1000

a = 2

d = 2

1000 = 2 + (n - 1)*2

998/2 = (n - 1) * 2 / 2

499 =  n - 1

n = 500

Solution odd

l = 1001

a = 1

d = 2

1001 = 1 + (n - 1)*2

1000 =  (n - 1)*2

1000/2 =  (n - 1)2/2

500 =  n - 1

501 = n

Sum Even of even numbers from 1 to 1001

Givens

a = 2

n = 500

l = 1000

Equation

Sum = (a + l ) * n / 2

Solution

Sum = (2 + 1000)*500/2

Sum = 1002 * 250

Sum = 250500

Sum of Odd numbers from 1 to 1001

a = 1

l = 1001

n = 501

Equation

sum = (a + l)*n/2

sum = (1 + 1001) * 501

sum = (1002)*501 / 2

Sum =  251001

Answer

m - n = 251001 - 250500 = 501

6 0
3 years ago
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