1/2x+20=1/3x+30
Subtract 20 on both sides
1/2x=1/3x+10
Subtract 1/3x on both sides
1/6x=10
Multiply by 6 on both sides
X=60
Answer:
The percent decrease is approximately ![10.75\%](https://tex.z-dn.net/?f=10.75%5C%25)
(Don't know what you are expected to round to.)
Step-by-step explanation:
Percent change can be calculated by doing:
![\frac{\text{original}-\text{new}}{\text{original}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Boriginal%7D-%5Ctext%7Bnew%7D%7D%7B%5Ctext%7Boriginal%7D%7D)
Then you multiply the result to covert it to a percentage.
Let's use this formula:
![\frac{5831 \text{thousand}-5204 \text{ thousand }}{5831 \text{thousand}}](https://tex.z-dn.net/?f=%5Cfrac%7B5831%20%5Ctext%7Bthousand%7D-5204%20%5Ctext%7B%20thousand%20%7D%7D%7B5831%20%5Ctext%7Bthousand%7D%7D)
![\frac{\text{thousand}}{\text{thousand}} \cdot \frac{5831-5204}{5831}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Bthousand%7D%7D%7B%5Ctext%7Bthousand%7D%7D%20%5Ccdot%20%5Cfrac%7B5831-5204%7D%7B5831%7D)
![\frac{5831-5204}{5831}](https://tex.z-dn.net/?f=%5Cfrac%7B5831-5204%7D%7B5831%7D)
![\frac{627}{5831}](https://tex.z-dn.net/?f=%5Cfrac%7B627%7D%7B5831%7D)
approximately
Now the answer as a percent is
approximately.
The percent decrease is approximately ![10.75\%](https://tex.z-dn.net/?f=10.75%5C%25)
Answer:
SA = 105 in^2
Step-by-step explanation:
To find surface area, find the area of all the shapes and add it all together. This shape has 4 triangle faces. They are all the same. So we can find one of them and times by 4.
Area of a triangle:
A = 1/2b•h
= 1/2• 5 • 8
= 1/2 • 40
= 20
One triangle has area 20, so times by 4 (bc four triangles)
4•20
= 80
Area of square 5•5
= 25
Add the areas:
80 + 25
= 105 sq in
Answer:
d(1) = -3 and d(2)= -28
Step-by-step explanation:
Given that the distance d, in centimeters, that a diving board bends below its resting position when you stand at its end is dependent on your distance x, in meters, from the stabilized point
![d(x)=-4x^3+x^2](https://tex.z-dn.net/?f=d%28x%29%3D-4x%5E3%2Bx%5E2)
For finding out the distances for x=1 and x=2
let us substitute 1 and 2 for x
![d(1) = -4(1^3)+1^2 = -3](https://tex.z-dn.net/?f=d%281%29%20%3D%20-4%281%5E3%29%2B1%5E2%20%3D%20-3)
![d(2) = -4(2^3)+2^2 \\= -28](https://tex.z-dn.net/?f=d%282%29%20%3D%20-4%282%5E3%29%2B2%5E2%20%5C%5C%3D%20-28)
d(1) = -3 and d(2)= -28