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eimsori [14]
3 years ago
10

Help me again please.

Mathematics
1 answer:
PtichkaEL [24]3 years ago
7 0

Answer:

m=\frac{8}{5}

Step-by-step explanation:

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If I leave a cinema at 12.00am and arrive at 12.00pm how many hours are that.
spayn [35]

Answer:

a.12 hours

Step-by-step explanation:

12 am (00:00) represents midnight and 12 pm is noon (pm represents noon - after noon)so the time passes between 12 am to 12 pm is 12 hours

5 0
3 years ago
What are the slope and y-intercept of the graph of the given equation? y = 1.9x + 2.5
trapecia [35]

Answer:

The slope <em>m</em> is 1.9 and the y-intercept <em>b</em> is 2.5.

Step-by-step explanation:

This is in slope-intercept form, y=<em>m</em>x+<em>b</em>, where <em>m</em> is slope and <em>b</em> is the y-intercept.

y = 1.9x + 2.5 means that <em>m </em>is 1.9 and <em>b</em> is 2.5.

8 0
3 years ago
How to factor -2 out of -6x+10
KIM [24]
Just divide -6x+10 by -2 and take out what's common.

-6x divided by -2 would be 3x.
10 divided by -2 would be -5.

So the answer is -2(3x-5).

\sf\ Answer: -2(3x-5)
5 0
4 years ago
The perimeter of a rectangle is 34 units. it's width is 6.5 units. Write an equation to determine the length of the rectangle
gayaneshka [121]
The equation would be 34x2+6.5x2
6 0
3 years ago
At a large Midwestern university, a simple random sample of 100 entering freshmen in 1993 found that 20 of the sampled freshmen
guajiro [1.7K]

Answer:

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

p1 -> 1993

20 out of 100, so:

p_1 = \frac{20}{100} = 0.2

s_1 = \sqrt{\frac{0.2*0.8}{100}} = 0.04

p2 -> 1997

10 out of 100, so:

p_2 = \frac{10}{100} = 0.1

s_2 = \sqrt{\frac{0.1*0.9}{100}} = 0.03

Distribution of p1 – p2:

p = p_1 - p_2 = 0.2 - 0.1 = 0.1

s = \sqrt{s_1^2+s_2^2} = \sqrt{0.04^2 + 0.03^2} = 0.05

Confidence interval:

p \pm zs

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.  

The lower bound of the interval is:

p - zs = 0.1 - 1.645*0.05 = 0.01775&#10;

The upper bound of the interval is:

p + zs = 0.1 + 1.645*0.05 = 0.18225&#10;

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

6 0
3 years ago
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