(-6) + 3 = -3 ;
The negative integer is -6; the positive integer is 3.
Answer:
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QUADRATIC EQUATION
x²- 4x = 6
(x - 2)²- 4 = 6
(x - 2)² = 10
x - 2 = ±10
x = ±10+2
x = -8, 12
Answer:
the solution of the system is:
x = 1 and y = 2.
Step-by-step explanation:
I suppose that we want to solve the equation:
-6*x + 6*y = 6
6*x + 3*y = 12
To solve this, we first need to isolate one of the variables in one of the equations.
Let's isolate y in the first equation:
6*y = 6 + 6*x
y = (6 + 6*x)/6
y = 6/6 + (6*x)/6
y = 1 + x
Now we can replace this in the other equation:
6*x + 3*(1 + x) = 12
6*x + 3 + 3*x = 12
9*x + 3 = 12
9*x = 12 - 3 = 9
x = 9/9 = 1
Now that we know that x = 1, we can replace this in the equation "y = 1 + x" to find the value of y.
y = 1 + (1) = 2
Then the solution of the system is:
x = 1 and y = 2.
Answer:
6x^2 - 3x
Step-by-step explanation:
3x (2x-1)
multiply 3x by 2x -> 6x^2
multiply 3x by -1 -> -3x
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