Answer:you solve on each sides like normal then your equation will come out as “not a solution”
Step-by-step explanation:
13=-7
Answer:
√2
Step-by-step explanation:
Solving the given expression step by step:
![\frac{\sqrt{36} }{\sqrt{18} } = \frac{6}{3\sqrt{2} }\ \ \ [\because \sqrt{36} = 6 \ and \ \sqrt{18} = 3\sqrt{2}] \\ = \frac{3 \times 2}{3\sqrt{2} } = \frac{ 2}{\sqrt{2} }= \sqrt{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B36%7D%20%7D%7B%5Csqrt%7B18%7D%20%7D%20%3D%20%5Cfrac%7B6%7D%7B3%5Csqrt%7B2%7D%20%7D%5C%20%5C%20%5C%20%5B%5Cbecause%20%5Csqrt%7B36%7D%20%3D%206%20%5C%20and%20%5C%20%5Csqrt%7B18%7D%20%3D%203%5Csqrt%7B2%7D%5D%20%5C%5C%20%3D%20%5Cfrac%7B3%20%5Ctimes%202%7D%7B3%5Csqrt%7B2%7D%20%7D%20%3D%20%5Cfrac%7B%202%7D%7B%5Csqrt%7B2%7D%20%7D%3D%20%5Csqrt%7B2%7D)
We rationalize denominator and change it into a simpler form as soon as possible.
Answer:
Step-by-step explanation:
Given: quadrilateral ABCD inscribed in a circle
To Prove:
1. ∠A and ∠C are supplementary.
2. ∠B and ∠D are supplementary.
Construction : Join AC and BD.
Proof: As, angle in same segment of circle are equal.Considering AB, BC, CD and DA as Segments, which are inside the circle,
∠1=∠2-----(1)
∠3=∠4-----(2)
∠5=∠6-------(3)
∠7=∠8------(4)
Also, sum of angles of quadrilateral is 360°.
⇒∠A+∠B+∠C+∠D=360°
→→∠1+∠2+∠3+∠4+∠5+∠6+∠7+∠8=360°→→→using 1,2,3,and 4
→→→2∠1+2∠4+2∠6+2∠8=360°
→→→→2( ∠1 +∠6) +2(∠4+∠8)=360°⇒Dividing both sides by 2,
→→→∠B + ∠D=180°as, ∠1 +∠6=∠B , ∠4+∠8=∠B------(A)
As, ∠A+∠B+∠C+∠D=360°
∠A+∠C+180°=360°
∠A+∠C=360°-180°------Using A
∠A+∠C=180°
Hence proved.
credit: someone else
Answer:
4
Step-by-step explanation:
use pythagoeron theorem
9^2-7^2=x^2
x^2=32
x=4
Answer: A. preserves length, angle measures and distance between points
Rigid motions or isometries are any of the three transformations below
- translation (aka shifting)
- rotation
- reflection
Any of those three transformations will keep the figure the same size and shape. That means distances between any two points are kept the same, and angle measures are kept the same as well. Everything is kept the same. The only difference is that the figure is in a different location, is rotated somehow, or it is reflected some way. You can use a series of transformations to undo everything to get the original figure back.
If you wanted to change the size of the figure, then you would apply dilation, which isn't an isometry.
