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professor190 [17]
3 years ago
15

In two or more complete sentences explain how to balance the chemical equation, KClO3 ⟶ KCl + O2 and include all steps. Write yo

ur response in the essay box below.
Chemistry
1 answer:
Serggg [28]3 years ago
5 0

Answer:

2KClO3 -------> 2KCl + 3O2

Explanation:

First, in balancing a chemical reaction such as the one given in the question, you should understand that for an equation to be balanced, the number of atoms and ions on both sides of the equation that is the right and left side must be equal. This follows the law of conservation of mass which tells us that matter can neither be created nor destroyed but can be changed into another form.

Next is to begin balancing the equation by identifying and writing down the substances given:

KCl03 ---------> KCl + O2

Next is to count he number of the individual atoms on each side and find out if they are the same on both sides and if not you must follow the next step.

Add a corresponding number and use it to multiply the atoms involved

KClO3 ---------> KCl + O2

Oxygen is 3 on the left side and two on the other side, so we multiply the left hand side by 2 and the right hand side by 3

2KClO3 -----> KCl + 3O2

The potassium and Chlorine are no longer balanced, so you multiply the right had=nd side of KCl by 2.

2KClO3 -----> 2KCl + 3O2

The reactionis herefore balanced as both sides have equal number of atoms and ions.

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Balance the following redox equation in acidic solution using the smallest integers possible and select the correct coefficient
romanna [79]

Answer:

Coefficient of H^{+}(aq) is more than 4

Explanation:

Oxidation: Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)

  • Balance charge: Sn^{2+}(aq)-2e^{-}\rightarrow Sn^{4+}(aq)......(1)

Reduction: Cr_{2}O_{7}^{2-}(aq)\rightarrow Cr^{3+}(aq)

  • Balance Cr: Cr_{2}O_{7}^{2-}(aq)\rightarrow 2Cr^{3+}(aq)
  • Balance O and H in acidic medium: Cr_{2}O_{7}^{2-}(aq)+14H^{+}(aq)\rightarrow 2Cr^{3+}(aq)+7H_{2}O(l)
  • Balance charge: Cr_{2}O_{7}^{2-}(aq)+14H^{+}(aq)+6e^{-}\rightarrow 2Cr^{3+}(aq)+7H_{2}O(l).......(2)

[3\times Equation-(1)]+Equation(2) gives balanced equation:

3Sn^{2+}(aq)+Cr_{2}O_{7}^{2-}(aq)+14H^{+}(aq)\rightarrow 3Sn^{4+}(aq)+2Cr^{3+}(aq)+7H_{2}O(l)

So coefficient of H^{+}(aq) is more than 4

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3 years ago
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2H2(g)+O2(g)→2H2O(l)
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Answer:

6.4g

Explanation:

32g of O2 produce 36g of H2O/5.70g of O2 produce x the answer is 6.4g

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