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professor190 [17]
3 years ago
15

In two or more complete sentences explain how to balance the chemical equation, KClO3 ⟶ KCl + O2 and include all steps. Write yo

ur response in the essay box below.
Chemistry
1 answer:
Serggg [28]3 years ago
5 0

Answer:

2KClO3 -------> 2KCl + 3O2

Explanation:

First, in balancing a chemical reaction such as the one given in the question, you should understand that for an equation to be balanced, the number of atoms and ions on both sides of the equation that is the right and left side must be equal. This follows the law of conservation of mass which tells us that matter can neither be created nor destroyed but can be changed into another form.

Next is to begin balancing the equation by identifying and writing down the substances given:

KCl03 ---------> KCl + O2

Next is to count he number of the individual atoms on each side and find out if they are the same on both sides and if not you must follow the next step.

Add a corresponding number and use it to multiply the atoms involved

KClO3 ---------> KCl + O2

Oxygen is 3 on the left side and two on the other side, so we multiply the left hand side by 2 and the right hand side by 3

2KClO3 -----> KCl + 3O2

The potassium and Chlorine are no longer balanced, so you multiply the right had=nd side of KCl by 2.

2KClO3 -----> 2KCl + 3O2

The reactionis herefore balanced as both sides have equal number of atoms and ions.

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Oxygen gas, generated by the reaction 2KClO3(s)---2KCl(s)+3O2(g), is collected over water at 27•C in 3.72L vassel at a total pre
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Answer:

moles = 0.093 moles

Explanation:

In this case, we know that this reaction is taking plave in a vessel that has a 730 torr of total pressure.

The total pressure is a value obtained by:

Pt = Pwater + PO2

We need to know the pressure of O2, because then, with stoichiometry, we can calculate the moles of KClO3

The pressure of oxygen is:

PO2 = 730 - 26 = 704 Torr

Now, this pressure is in Torr, and we need to convert it to Atm, so:

704 Torr / 760 Torr = 0.9263 atm

Now, let's use the ideal gas equation:

PV = nRT

With this expression, we will calculate the moles of O2, and then, the moles of KClO3:

n = PV/RT

R = 0.082 L atm /K mol

P = 0.9263 atm

V = 3.72 L

T = 27 + 273 = 300 K

Replacing the data:

n = 0.9263 * 3.72 / 300 * 0.082

n = 0.14 moles

Finally, by stoichiometry, we know that 2 moles of KClO3 produces 3 moles of O2, so:

moles of KClO3 = 0.14 * 2/3 = 0.093 moles of KClO3

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