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2 years ago

PLEASE HELP me ANSWER these!!! My grade depends on it!!

1 answer:

8 0

M (Mean) = 20,500;
SD (Standard Deviation) = 55
1 ) 20,555 = 20,500 + 55 = M + 1 SD
Answer: 50% + 34.1% = 84.1%
2 ) 20.610 = 20,000 + 110 = M + 2 SD
Answer: 10% - ( 50% + 34.1% + 13.6% ) = 100% - 97.7% = 2.3%
3 ) 20,445 = 20,500 - 55 = M - 1 SD
Answer: 50% - 34.1% = 15.9%

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When you are 14 and you save 25 cents everyday how much would you when you are 60v years old?

Minchanka [31]

60-14 , 25x46=1150. Thats how you solve it

4 0

3 years ago

A retailer who sells backpacks estimates that by selling them for x dollars each, she will be able to sell 100−x backpacks each

zvonat [6]

Answer:

x = 50

R = $2500

Step-by-step explanation:

Given in the question a quadratic equation,

−x² + 100x

To find the selling price, x, which will give highest revenue, y, we will find maximum value of parabola curve −x² + 100x

The value of -b/2a tells you the value x of the vertex of the function

−x² + 100x

here a = -1

b = 100

Selling price = -(100)/2(-1)

= 50

R = −(50)² + 100(50)

= 2500

8 0

3 years ago

Which of the following is not equal to sin⁡(-230°)?

xenn [34]

From trigonometry we know that:

if $sin(\theta)=sin(\alpha)$

then, $\theta=n\pi+(-1)^n\alpha$ (where $n$ is an integer)

This can be rewritten in degrees as:

$\theta=n(180^{\circ})+(-1)^n\alpha$ .............(Equation 1)

Now, in our case, $\alpha=-230^{\circ}$

Therefore, (Equation 1) can be written as:

$\theta=n(180^{\circ})+(-1)^n(-230^{\circ})$ ..........(Equation 2)

Now, to find the correct options all that we have to do is replace n by relevant integers and find the values of $\theta$ that match.

For n=2, (Equation 2) gives us: $\theta=2\times 180^{\circ}+(-1)^2(-230^{\circ})=360^{\circ}-230^{\circ}=130^{\circ}$ .

Thus, $sin(230^{\circ})=sin(130^{\circ})$

Now, we know that: $-sin(-50^{\circ})=sin(50^{\circ})$

Let n=-1, then:

$\theta=(-1)\times 180^{\circ}+(-1)^{-1}(-230^{\circ})=-180^{\circ}+230^{\circ}=50^{\circ}$

Thus, $sin(-230^{\circ})=-sin(-50^{\circ})$

Likewise, $sin(-230^{\circ})=sin(50^{\circ})$

Only the last option $sin(-50^{\circ})$ will never match $sin(-230^{\circ})$ because no integral value of $n$ will ever give $\theta=-50^{\circ}$

Thus the last option is the correct option.

3 0

2 years ago

Read 2 more answers

How do I solve this out??

GuDViN [60]

<h3>Answer:</h3>

(x, y) = (7, -5)

<h3>Step-by-step explanation:</h3>

It generally works well to follow directions.

The matrix of coefficients is ...

$\left[\begin{array}{cc}2&4\\-5&3\end{array}\right]$

Its inverse is the transpose of the cofactor matrix, divided by the determinant. That is ...

$\dfrac{1}{26}\left[\begin{array}{ccc}3&-4\\5&2\end{array}\right]$

So the solution is the product of this and the vector of constants [-6, -50]. That product is ...

... x = (3·(-6) +(-4)(-50))/26 = 7

... y = (5·(-6) +2·(-50))/26 = -5

The solution using inverse matrices is ...

... (x, y) = (7, -5)

7 0

2 years ago

Line C passes through the points (0, -5) and (2, -3). Line D has the equation y = 2/5x - 3 which statement is true

Degger [83]

Line c has a positive slope since it goes from -5 to -3. and kind d’s slope is 2/5 which is also positive so the answer is a)

4 0

2 years ago

Read 2 more answers