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Serhud [2]
3 years ago
9

What is one thousand five hundred divided by five equal

Mathematics
2 answers:
kirill115 [55]3 years ago
8 0

Answer:

300

Step-by-step explanation:

\frac{1500}{5}  = 300

It's very easy to find if you use a calculator.

To know whether that the answer is correct or wrong you can do like this.

300 \times 5 = 1500

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>

<em>thanks</em><em>.</em>

Vikki [24]3 years ago
5 0

Answer: 300

We know that 5×3=15. Since we are trying to get 1500 we Multiply 300×5 and get 1500.

<u>How do we know?</u>

  • As you can see if you cross out 2 of the 0 in 300 you have 3×5. When you multiply it you get 15.
  • Also if you cross out 1 of the 0 in 300 you have 30×5. When you multiply that you get 150.

As you see when you still multiply either of those problems you have 15 in it. So we should know 300×5=1500.

Note: We can also multiply 500×3 and get 1500. You still get the same answer but just switched numbers.

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Given the quadratic equation <img src="https://tex.z-dn.net/?f=y%20%3D%202%28x%20-1%29%5E%7B2%7D%20%2B%208" id="TexFormula1" tit
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Answer:

Part 1) "a" value is 2

Part 2) The vertex is the point (1,8)

Part 3) The equation of the axis of symmetry is x=1

Part 4) The vertex is a minimum

Part 5) The quadratic equation in standard form is y=2x^{2}-4x+10

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

y=a(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

if a > 0 then the parabola open upward (vertex is a minimum)

if a < 0 then the parabola open downward (vertex is a maximum)

The equation of the axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex

so

x=h

In this problem we have

y=2(x-1)^{2}+8 -----> this is the equation in vertex form of a vertical parabola

The value of a=2

so

a>0 then the parabola open upward (vertex is a minimum)

The vertex is the point (1,8)

so

(h,k)=(1,8)

The equation of the axis of symmetry is x=1

The equation of a vertical parabola in standard form is equal to

y=ax^{2}+bx+c

Convert vertex form in standard form

y=2(x-1)^{2}+8

y=2(x^{2}-2x+1)+8

y=2x^{2}-4x+2+8

y=2x^{2}-4x+10

see the attached figure to better understand the problem

7 0
3 years ago
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