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2 years ago

Evaluate the statistics expression:39C1

Mathematics

1 answer:

Aleksandr-060686 [28]2 years ago

4 0

<h3>Answer: 39</h3>

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Explanation:

You can use the nCr formula shown below

$_n C _r = \frac{n!}{r!*(n-r)!}$

where n = 39 and r = 1. However, you could also use the identity

$_n C _{1} = n$

which basically says there are n ways to pick 1 item if you are given a choice of n items. In this specific case, we have 39 items total, and there are 39 ways to pick one item.

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2 years ago

Need help simplifying this

diamong [38]

The simplified answer is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$ .

Step-by-step explanation:

$$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term $(\frac{3x+y}{3x+y})$ and 2nd term by $(\frac{z+2x}{z+2x})$

= $\frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= $\frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}$

Now, the denominators are same, you can subtract it.

= $\frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

= $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

Thus the simplified solution is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

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2 years ago

I will name you brainliest!

liq [111]

Answer:

Step-by-step explanation:

a specific shade of red nail polish requires 7 parts of red to 2 parts of yellow. A mixture contains 35 quarts of red and 8 quarts of yellow.

How can you fix the mixture to make the correct shade of red?

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The red:yellow ratio is 7:2, we can write the mixture as 7%2F9 or 77.8% red

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The existing mixture of 35:8 is a 43 quart mixture and can be written as: 35%2F43 or 81.4% red

:

we need to add yellow to reduce the per cent of red

:

Let y = amt of yellow required to do this

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7%2F9*(y+43) = 35

Multiply both sides by 9

7(y+43) = 9 * 35

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y = 2 quarts of yellow to be added, for total mixture of 45 quarts

;

:

Check this, it still contains 35 quarts of red but the percentage has changed

35%2F45 = 77.8% red which is what we want, a ratio of 7:2

here you go i hope it helps

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