Answer:
The correct interpretation of the interval is;
C. We are 95 percent confident that for every one-year increase in the age of black bears in the sample, the average increase in the weights of those black bears is between 7.0 and 18.4 pounds
Step-by-step explanation:
The given parameters are;
The number of black bears = 12 black bears
The relationship investigated by the zoologist is the relationship between years, 'x', and the weight 'y' in pounds
Therefore, we have;
The 95% confidence interval for estimating the population slope of linear regression line predicting weight in tens of pounds based on the age in years is given by 1.272 ± 0.570
Therefore, we get the confidence interval as follows;
10 × (1.272 - 0.570) < < 10 × (1.272 + 0.570)
Which gives;
7.02 < < 18.42
Therefore, we are 95% that the increase in age of a black bear by one year will see an increase in the average weight of black bear by between 7.02 and 18.42 pounds
9.5 * 10^6 = 9,500,000
4.0 * 10^2 = 400
9,500,000 * 400 = 3,800,000,000 = 3.8 * 10^9
Answer:
8.1 moles
Step-by-step explanation:
Given parameters: Mass of water to be decomposed = 29.2g Unknown: Number of moles of oxygen. Solution: To solve this problem, we first write the balanced reaction equation : 2H₂O → 2H₂ + O₂ Now convert the given mass of the water to number of moles; Number of moles of water = Molar mass of water = 2(1) + 16 = 18g/mol Number of moles of water = = 16.2moles From the balanced reaction equation: 2 moles of water produced 1 mole of oxygen gas; 16.2 mole of water will produce = 8.1moles of oxygen gas
Hope this helps you :3
Your answer is 40. Simply divide 1200 by 30 and you will get 40.
0.2916666..... = 1458333/5000000