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andrew11 [14]
3 years ago
10

Need help please help me

Mathematics
1 answer:
ANTONII [103]3 years ago
3 0
Megan:
x to the one third power =  x ^{1/3}
<span>x to the one twelfth power = </span>x ^{1/12}

<span>The quantity of x to the one third power, over x to the one twelfth power is:
</span>\frac{x ^{1/3}}{x ^{1/12}}
<span>
Since </span>\frac{ x^{a} }{ x^{b} } = x ^{a-b}
then \frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12}

Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4

\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12} = x^{1/4}


Julie:
x times x to the second times x to the fifth = x * x² * x⁵

<span>The thirty second root of the quantity of x times x to the second times x to the fifth is
</span>\sqrt[32]{x* x^{2} * x^{5} }
<span>
Since </span>x^{a}* x^{b}= x^{a+b}
Then \sqrt[32]{x* x^{2} * x^{5} }= \sqrt[32]{ x^{1+2+5} } =\sqrt[32]{ x^{8} }

Since \sqrt[n]{x^{m}} = x^{m/n} }
Then \sqrt[32]{ x^{8} }= x^{8/32} = x^{1/4}

Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.
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If a car has tires with a radius of 1.5 ft and the tires are spinning at 840 rpm (revolutions per
tamaranim1 [39]

Answer:

89·98 mph

Step-by-step explanation:

First, we get the circumference of the tires:

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Circumference = 3·142 × 3

Circumference = 9·426 ft

The circumference of the tire is equal to one round.

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840 rounds = ?

We cross multiply to get the length that the tires would cover in a minute

= <u>840 × 9·426</u>

       1

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60 minutes = ?

<u>60 × 7917·84</u>

          1

= 475070·4 ft

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475070·4 feet = ?

<u>475070·4 × 1</u>

     5280

475070·4 ÷ 5280 = speed of the car in mph

89·97545

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hope this helps! =)

5 0
3 years ago
7.2 = 8t<br> t = ??? <br> I need a little help with this one <br> sorry...
cluponka [151]
You have to get t alone so you divide both sides by 8
7.2/8= 0.9 and 8t/8=t
T=0.9
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2 years ago
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