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kobusy [5.1K]
3 years ago
5

A quadratic equation of the form 0=ax2+bx+c has a discriminant value of -16. How many real number solutions does the equation ha

ve?
Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
8 0

Answer: There will be no real solutions

Explanation: If the discriminant (the part under the radical in the numerator of the quadratic equation) is less than 0, there are no real solutions. If positive, there will be two real solutions. If 0, there will be one.

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Answer:

Step-by-step explanation:

The point ( -2 , 3) lies in the 2nd quadrant

Point are generally in the form (x , y). The point you need to plot is ( -2 , 3) which means the value of x = -2 and the value of y = 3.

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A computer store has certain software on sale at 3 for $20.00, with a limit of 3 at the sale price. Additional
alexgriva [62]

Answer:

a) y = 9.95(x-3) + 20.00

b) Cost of 5 software packages = $39.90

Step-by-step explanation:

Given that:

Cost of 3 software at sale = $20

Cost of regular = $9.95

Let,

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We will subtract 3 from x because they cost $20.

y be the total cost.

y = 9.95(x-3)+ 20.00

Putting x=5 in expression

y = 9.95(5-3) + 20.00

y = 2(9.95) + 20.00

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y = $39.90

Hence,

a) y = 9.95(x-3) + 20.00

b) Cost of 5 software packages = $39.90

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Vlad1618 [11]

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Step-by-step explanation:

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Answer:

√41

Step-by-step explanation:

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Answer:

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