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kobusy [5.1K]
3 years ago
5

A quadratic equation of the form 0=ax2+bx+c has a discriminant value of -16. How many real number solutions does the equation ha

ve?
Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
8 0

Answer: There will be no real solutions

Explanation: If the discriminant (the part under the radical in the numerator of the quadratic equation) is less than 0, there are no real solutions. If positive, there will be two real solutions. If 0, there will be one.

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What is the decimal equivalent of 9.7x10^5
Usimov [2.4K]

Answer:

B. 970,000

Step-by-step explanation:

<u>M</u><u>o</u><u>v</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>d</u><u>e</u><u>c</u><u>i</u><u>m</u><u>a</u><u>l</u><u> </u><u>5</u><u> </u><u>p</u><u>l</u><u>a</u><u>c</u><u>e</u><u>s</u><u> </u><u>t</u><u>o</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>r</u><u>i</u><u>g</u><u>h</u><u>t</u><u>,</u><u> </u><u>s</u><u>i</u><u>n</u><u>c</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>e</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>i</u><u>s</u><u> </u><u>a</u><u> </u><u>p</u><u>o</u><u>s</u><u>i</u><u>t</u><u>i</u><u>v</u><u>e</u><u> </u><u>5</u><u>.</u>

9.7 x 10⁵ = 970,000.

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5 0
3 years ago
Write the equation of the parabola in vertex form
Tpy6a [65]

Answer:

y = -(x - 2)^2.

Step-by-step explanation:

Vertex form is a(x - b)^2 + c   where  a is a constant and (b, c) is the vertex.

Here b = 2 and c = 0

So we have:

y = a( x - 2)^2 + 0

When x = 4 y = -4 so:

-4 = a( 4 - 2)^2

a = -4/2^2 = -1

So the required equation is

y = -(x - 2)^2.

8 0
3 years ago
In ΔFGH, the measure of ∠H=90°, HF = 1.2 feet, and FG = 5.7 feet. Find the measure of ∠F to the nearest tenth of a degree.
amid [387]

Answer:

77.8

Step-by-step explanation:

don't ask

3 0
3 years ago
A cone with volume 5000 m³ is dilated by a scale factor of 15. What is the volume of the resulting cone? Enter your answer in th
Rasek [7]

Answer:

40\ m^{3}

Step-by-step explanation:

we know that

If two figures are similar then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z-----> scale factor

x-----> the volume of the dilated cone

y-----> the volume of the original cone

z^{3}=\frac{x}{y}

In this problem we have

z=1/5

y=5,000\ m^{3}

substitute and solve for x

(1/5)^{3}=\frac{x}{5,000}

(1/125)=\frac{x}{5,000}

x=5,000/125=40\ m^{3}

5 0
3 years ago
Read 2 more answers
Select all of the coefficients in the expression. 12xy3 + 2x5y + 4x5y2 + 7x5y.
MAVERICK [17]
Coefficients are the numbers multiplied by the variables (letters)..not the exponents

so ur coefficients are : 12,2,4,7 <==
8 0
3 years ago
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