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kobusy [5.1K]
3 years ago
5

A quadratic equation of the form 0=ax2+bx+c has a discriminant value of -16. How many real number solutions does the equation ha

ve?
Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
8 0

Answer: There will be no real solutions

Explanation: If the discriminant (the part under the radical in the numerator of the quadratic equation) is less than 0, there are no real solutions. If positive, there will be two real solutions. If 0, there will be one.

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I need help with these two trigonometry problems.
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Answer:

Step-by-step explanation:

For 5 we need to use sine law.

The thing about sine law is that we need to look at the triangle sides that are in front of the angles.

In this case: <B = 30°

the triangle side that is in front of this angle is AC which is 4 cm.

Then we got <C = 61°, and the triangle side in front of it is AB, which is what we need to find.

According to sine law:

\frac{sin B}{AC} = \frac{sin C}{AB}

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Question 6:

Wow it's pretty crowded, but they probably want us to use sine law as well. Let's write what we know:

<C  = 12°

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AC = ?

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AC = 96.59

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8 0
2 years ago
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