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kobusy [5.1K]
3 years ago
5

A quadratic equation of the form 0=ax2+bx+c has a discriminant value of -16. How many real number solutions does the equation ha

ve?
Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
8 0

Answer: There will be no real solutions

Explanation: If the discriminant (the part under the radical in the numerator of the quadratic equation) is less than 0, there are no real solutions. If positive, there will be two real solutions. If 0, there will be one.

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Help me pls !!!<br><br> answer all pls
polet [3.4K]
1. We assume, that the number 128 is 100% - because it's the output value of the task. 
<span>2. We assume, that x is the value we are looking for. </span>
<span>3. If 128 is 100%, so we can write it down as 128=100%. </span>
<span>4. We know, that x is 51% of the output value, so we can write it down as x=51%. </span>
5. Now we have two simple equations:
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2) x=51%
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128/x=100%/51%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 51% of 128

128/x=100/51
<span>(128/x)*x=(100/51)*x       - </span>we multiply both sides of the equation by x
<span>128=1.96078431373*x       - </span>we divide both sides of the equation by (1.96078431373) to get x
<span>128/1.96078431373=x </span>
<span>65.28=x </span>
x=65.28

<span>now we have: </span>
<span>51% of 128=65.28</span>
8 0
3 years ago
Solve each equation for the variable
motikmotik

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X= -50

Step-by-step explanation:

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mario62 [17]

Answer:

7) 1

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10) 4/3

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Step-by-step explanation:

to find the slope when given to points ... minus the y values and x values

formula :

y - y

------  =  slope

x - x

4 0
3 years ago
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