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kvv77 [185]
3 years ago
5

Find the equation of the ellipsoid passing through the points (±6,0,0),(0,±7,0) and (0,0,±5)

Mathematics
1 answer:
zzz [600]3 years ago
3 0

The standard equation of an ellipsoid is given by

\frac{x^2}{a^2}+\frac{y^2}{b^2}+\frac{z^2}{c^2}=1

where a, b and c are semi axes length.  It means the ellipsoid is passing through the points (±a,0,0),(0,±b,0) and (0,0,±c).

Now, we have been given that the ellipsoid is passing through the points  (±6,0,0),(0,±7,0) and (0,0,±5). Thus, we have

a=\pm 6\\
b=\pm 7\\
c=\pm 5\\

Therefore, the equation of the ellipsoid is given by

\frac{x^2}{(\pm 6)^2}+\frac{y^2}{(\pm 7)^2}+\frac{z^2}{(\pm 5)^2}=1\\
\\
\frac{x^2}{36} +\frac{y^2}{49} +\frac{z^2}{25} =1


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E
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Answer:

  44x +56y = 95

Step-by-step explanation:

To write the equation of the perpendicular bisector, we need to know the midpoint and we need to know the differences of the coordinates.

The midpoint is the average of the coordinate values:

  ((-2.5, -2) +(3, 5))/2 = (0.5, 3)/2 = (0.25, 1.5) = (h, k)

The differences of the coordinates are ...

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Then the perpendicular bisector equation can be written ...

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  44x +56y = 95 . . . . equation of the perpendicular bisector

8 0
4 years ago
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