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rjkz [21]
1 year ago
15

According to a survey conducted by the U.S. Department of Health and Human Services, about 50% of U.S. adults age 18 and older a

re registered as
organ donors. The survey had a margin of error of ±1.2%. a. Estimate the range of the actual percentages of U.S. adults who are registered organ donors. 51.2 to. 48.8. b. In 2019, there were an estimated 255,200,373 adults age 18 and older. Use your solution from part a to estimate the total number of U.S. adults who are registered organ donors to the nearest hundred thousand.
Mathematics
1 answer:
liraira [26]1 year ago
7 0

Using a confidence interval, we have that:

a) The range is from 48.8% to 51.2%.

b) Between 125,000 and 131,000 adults are registered organ donors.

<h3>What is a confidence interval?</h3>

A confidence interval is given by the <u>estimate plus/minus the margin of error</u>.

For this problem, we have that:

  • The estimate is of 50%.
  • The margin of error is of 1.2%.

The bounds of the range are given as follows:

  • 50% - 1.2% = 48.8%.
  • 50% + 1.2% = 51.2%.

Hence the range is from 48.8% to 51.2%.

<h3>What are the total numbers?</h3>

We have to find <u>48.8% and 51.2% of 255,200,373</u>, hence:

  • 0.488 x 255,200,373 = 124,537,782.
  • 0.512 x 255,200,373 = 130,662,591.

Rounded to hundredth thousand, between 125,000 and 131,000 adults are registered organ donors.

More can be learned about confidence intervals at brainly.com/question/25890103

#SPJ1

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<em><u>Solution:</u></em>

Given that we have to find the sum of 1\frac{7}{10} \text{ and } 3\frac{3}{5}

<em><u>Let us first convert the mixed fractions to improper fractions</u></em>

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1\frac{7}{10} = \frac{10 \times 1 + 7}{10} = \frac{10+7}{10} = \frac{17}{10}\\\\3\frac{3}{5} = \frac{5 \times 3 + 3}{5} = \frac{18}{5}

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When we divide 53 by 10 , the remainder is 3

Therefore, write 5 as a whole number and and 3 as numerator and 10 as denominator

\frac{53}{10} = 5\frac{3}{10}

Thus the sum of given mixed fraction is 5\frac{3}{10}

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