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Fynjy0 [20]
3 years ago
14

How to find a

Mathematics
2 answers:
Stells [14]3 years ago
5 0
Find the multiples of each denominator
In this case...
It would be 4, 8, 12
12

See when you come to a common number

(3×3)/(4×3) to get 12 + (5×1)/(12×1) whatever u do to the bottom do to the top
9/12 + 5/12
14/12
7/6
Olegator [25]3 years ago
4 0
In reality your common denominator should be the Least Common Multiple. The LCM is the product of highest occurring primes of the numbers prime factorizations...

4=2*2, and 12=2*2*3.  So the LCM is 2*2*3=12  Now that you know what the least common multiple is we can say that:

(3/4)(3/3)+5/12

9/12+5/12

(9+5)/12

14/12

7/6  which should be converted to a mixed number as this is an improper fraction...

(6+1)/6

1+1/6

1 1/6
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The question is in the photo. it is asking for 2 answers
Alex777 [14]

9514 1404 393

Answer:

  • 2nd force: 99.91 lb
  • resultant: 213.97 lb

Step-by-step explanation:

In the parallelogram shown, angle B is the supplement of angle DAB:

  ∠B = 180° -77°37' = 102°23'

Angle ACB is the difference of angles 77°37' and 27°8', so is 50°29'.

Now, we know the angles and one side of triangle ABC. We can use the law of sines to solve for the other two sides.

  BC/sin(A) = AB/sin(C)

  AD = BC = AB·sin(A)/sin(C) = (169 lb)sin(27°8')/sin(50°29') ≈ 99.91 lb

 AC = AB·sin(B)/sin(C) = (169 lb)sin(102°23')/sin(50°29') ≈ 213.97 lb

7 0
3 years ago
Evaluate if a = 3, b = 4<br>a² +6²<br>a-b​
____ [38]

Answer:

a^2 + 6^2:

    3^2 + 6^2

    9 + 36 = 45

answer: 45

a-b

    3-4

     -1

answer: -1

Step-by-step explanation:

3 0
3 years ago
Genetic Inheritance: Calculate probability of two children having the same genotype for achrondoplasia Achondroplasia is a commo
dimaraw [331]

Answer:

The correct answer is - 1/2 or 50% for first and second child to be affected.

Step-by-step explanation:

Achondroplasia is an autosomal dominant disorder. Autosomal dominant disorder refers to the presence of a single copy of the defective gene that is enough to lead to dwarfness.

A cross of achondroplasia (Aa) parent to a person of normal height (aa) result in half of their children will be affected with dwarfism and the other half will be normal.

a  cross between affected or dwarf  and normal parent

     Aa X aa

Punnett square:

         a a

A  Aa Aa

a aa aa

Aa- dwarfness

aa- normal height

The probability that both their first child and second child would have achondroplasia is

2/4 =1/2 or 50%.

6 0
3 years ago
Splitting the middle term 2x^2-9x+4
DiKsa [7]
(2x-1)(x-4)
Hereeeeeeeee
8 0
3 years ago
factorise the following 1. x²-2x+15.... 2. y²-19y+90​
Marta_Voda [28]

Answer:

1. x²-2x+15

This can't be factored, I've tried multiple ways now, but it just can't be factored.

2. y²-19y+90​

Let's factor y^2−19y+90

y^2−19y+90

The middle number is -19 and the last number is 90.

Factoring means we want something like

(y+_)(y+_)

Which numbers go in the blanks?

We need two numbers that...

   Add together to get -19

   Multiply together to get 90

Can you think of the two numbers?

Try -9 and -10:

   -9+-10 = -19

   -9*-10 = 90

Fill in the blanks in

(y+_)(y+_)

with -9 and -10 to get...

(y-9)(y-10)

Answer:

(y−9) (y−10)

3 0
3 years ago
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