All categories

3 years ago

Are the ratios 3:9 and 21:27 equivalent? Why or why not?

Mathematics

2 answers:

Nastasia [14]3 years ago

7 0

Answer:

Not equivalent

Step-by-step explanation:

Given:

3:9 and 21:27

We see that

21:27= 7:9

Comparing:

3:9 < 7:9

They have same denominator but different numerator, hence they are different

cluponka [151]3 years ago

6 0

Answer: No

Step-by-step explanation:

No there are not since 3 times 7 = 21 and 9 times 3 = 27. The numbers that are used to multiply for the answers, 7 and 9, are not the same so therefore both ratios are not equivalent.

You might be interested in

Find the value of n in the equation 6.2n – 3.7n = 85 + 45.

WINSTONCH [101]

Answer:

Value of n is 52

Step-by-step explanation:

So you have equation: 6.2n – 3.7n = 85 + 45

First, you need to collect the like terms and add the numbers on the other side: 2.5n=130

Now, you need to divide both sides of equation by 2.5. And you will get the answer. n=52

4 0

3 years ago

Please help I’m really need the help (NO LINKS ) (NO LYING ) PART 2

Naily [24]

Here multiple all your numbers together only for that question tho ok

7 0

3 years ago

Read 2 more answers

What is the value of k in the product of powers below?

balu736 [363]

k=2

Step-by-step explanation:

since all the base are 10 you use the powers to solve it.

so it would be -3+1+k=-3=-3

3 0

3 years ago

Read 2 more answers

given two squares, one with side length of 5 and the other with a side length of 7, what is the ratio of their areas?

Kaylis [27]

Answer:

25: 49

Step-by-step explanation:

$5*5:7*7\\25: 49$

7 0

3 years ago

In a shipment of 22 smartphones, 2 are defective. How many ways can a quality control inspector randomly test 4 smartphones, of

Eddi Din [679]

Answer:

Therefore the required ways are =190

Step-by-step explanation:

Combination: Combination is the number of selection of items from a collection of items where the order of selection does not matter.

Total number of smartphones =22

Defective phone = 2

Non defective phone = (22-2) =20

The control inspector randomly test 4 smartphones of which 2 are defective.

Non defective phone = 2

The ways to select 2 non defective phone is

$^{20}C_2=\frac{20!}{2!(20-2)!} =\frac{20!}{2!18!}=\frac{19\times 20}{2} =190$

The ways to select 2 defective phone is= $^2C_2=1$

Therefore the required ways are = (190×1) =190

5 0

4 years ago