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lina2011 [118]
4 years ago
11

In a bag there are 4 purple marbles, 3 green marbles, 10 yellow marbles. If a student draws one marble what is the sample space?

Mathematics
2 answers:
olya-2409 [2.1K]4 years ago
7 0

Answer:

U=\{Purple\hspace{3}marble,Yellow\hspace{3}marble,Green\hspace{3}marble\}

Step-by-step explanation:

Sample space is the group of all the specific results that can be obtained after random experimentation. Each of its components is defined as sample points or, simply, samples. It should be noted that, in certain cases, experiments may have two or more possible sample spaces. The experiment of taking a card from a Spanish deck, for example, has a sampling space made up of the numbers and another sample space made up of the suits. In this case the sample space is:

Sample\hspace{3}space=U=\{Purple\hspace{3}marble,Yellow\hspace{3}marble,Green\hspace{3}marble\}

Tema [17]4 years ago
3 0
Purple, Green, Yellow.


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Determine forms of exponential expressions please help
Irina-Kira [14]

Answer:

(36^t) / (6^(t^2)) is nonequivalent

(6^(t^2)) / (36^t) is equivalent

(6^(t^2)) * 36^t is nonequivalent

Step-by-step explanation:

We can use the exponential quotient law for this problem.

a^x / a^y = a^x - y

(6^(t^2)) / (6^2t) = (6^(t^2)) / (36^t)

4 0
2 years ago
4. Assume that the chances of a basketball player hitting a 3-pointer shot is 0.4 and the probability of hitting a free-throw is
vovikov84 [41]

Answer:

0.0334 = 3.34% probability that the player will make exactly 3 3-pointers and 5-free throws.

Step-by-step explanation:

For each 3-pointer shot, there are only two possible outcomes. Either the player makes it, or the player does not. The same is valid for free throws. This means that both the number of 3-pointers and free throws made are given by binomial distributions.

Since 3-pointers and free throws are independent, first we find the probability of making exactly 3 3-pointers out of 10, then the probability of making exactly 5 free throws out of 10, and then the probability that the player will make exactly 3 3-pointers and 5-free throws is the multiplication of these probabilities.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of making 3 3-pointers out of 10:

The chances of a basketball player hitting a 3-pointer shot is 0.4, which means that p = 0.4. So this is P(X = 3) when n = 10.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.21499

Probability of making 5 free throws out of 10:

The probability of hitting a free-throw is 0.65, which means that p = 0.65. The probability is P(X = 5) when n = 10.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{10,5}.(0.65)^{5}.(0.35)^{5} = 0.15357

Calculate the probability that the player will make exactly 3 3-pointers and 5-free throws.

0.21499*0.15537 = 0.0334

0.0334 = 3.34% probability that the player will make exactly 3 3-pointers and 5-free throws.

5 0
3 years ago
Find the distance between points A = (2, 0) and
allochka39001 [22]

Answer:

  9.2

Step-by-step explanation:

You want the distance between A(2, 0) and B(0, 9).

<h3>Distance</h3>

The distance formula is based on the Pythagorean theorem. It tells you the distance between (x1, y1) and (x2, y2) is ...

  d = √((x2 -x1)² +(y2 -y1)²)

For the given points, this becomes ...

  d = √((0 -2)² +(9 -0)²) = √(4+81) = √85

  d ≈ 9.2

The distance between A and B is about 9.2 units.

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2 years ago
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Vedmedyk [2.9K]

Answer:

the last three

Step-by-step explanation:

cuz im big brains like that

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Answer:2,5

Step-by-step explanation:

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