Please help me on this question and explain how you got your answer

Need help plssssss fast hurry plsss

Bond [772]

Answer:

50 ft2

Step-by-step explanation:

im not sure if this is right but this is what i got when i worked it out

5 0

3 years ago

Read 2 more answers

Here are the total scores of 10 students in an introductory statistics course.

cestrela7 [59]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Mean (m) = 72

Standard deviation (sd) = 10

Grading cutoff policy:

bottom 5% receive F

next 15% receive D

next 35% receive C

next 30% receive B

A) Give the cutoffs for the grades in this course in terms of standardized scores.

Standardized score for grade cutoff:

Locating the Zscore for the proportions on the z table :

Bottom 5% = 0.05 ; corresponding Zscore = - 1.645

next 15% receive D = (5 +15)% 0.20 ; corresponding Zscore = - 0.84

next 35% receive C = (20+35)% = 0.55 ; corresponding Zscore = 0.13

next 30% receive B = (55 + 30)% = 0.85 ; Corresponding Zscore = 1.04

B) Give the cutoffs in terms of actual total scores.

Recall:

Zscore = (x - m) /sd ; where x = actual score

x = sd*z + m

For F:

10*(-1.645) + 72 = 55.55

For D:

10*(-0.84) + 72 = 63.6

For C:

10*(0.13) + 72 = 73.3

For B:

10*(1.04) + 72 = 82.4

C) Do you think that this method of assigning grades is a good one?

Yes, it is good in terms of expressing scores around the mean such that score below are negative and those above are positive. However, it is a little bit ambiguous.

4 0

3 years ago

Given:

lys-0071 [83]

Answer:

$PS=13\text{ units}$

Step-by-step explanation:

So, we know that PR is 20, SR is 11, and QS is 5.

We also know that PQ is perpendicular to QR, forming the right angle at ∠Q.

We know all the side lengths except for PQ and PS (the one we want to find). Notice that if we find PQ first, we can then use the Pythagorean Theorem to find PS since we already know QS.

So, let's find PQ.

We can see that we can also use the Pythagorean Theorem on PQ. PQ, QR, and PR (the hypotenuse) will be our sides. So:

$(PQ)^2+(QR)^2=(PR)^2$