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Alchen [17]
3 years ago
7

Write the expression as a product: (4a–3)^2–16

Mathematics
1 answer:
Shkiper50 [21]3 years ago
5 0
((4a-3)-4)*((4a-3)+4) = (4a - 7)*(4a +1)
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Convert 3 2/7 into improper fractions <br><br> 21/7<br> 23/7<br> 41/7<br> None of the above
Vesnalui [34]
Hello,

The correct answer is B.

Further explanation: The first step is to multiply 3 by 7. That gives you 21, then add 21+2. Then put your denominator at the bottom.

Workspace:

3 * 7

=21

21 + 2

=23/7
5 0
3 years ago
Y=x+5 and y=3x-3 I need to get this in a ordered pair
koban [17]

9514 1404 393

Answer:

  (x, y) = (4, 9)

Step-by-step explanation:

Perhaps the ordered pair you want is the one that satisfies both equations.

We can find that by equating the expressions for y:

  x +5 = 3x -3

  8 = 2x . . . . . . . . add 3-x to both sides

  4 = x . . . . . . . . . divide by 2

  y = 4+5 = 9

The ordered pair is (x, y) = (4, 9).

4 0
3 years ago
David Herbert earns $2,475 a month as a security guard for Baldwin Enterprises.
ArbitrLikvidat [17]

Answer:

I dont think so my brain left the game

4 0
3 years ago
Read 2 more answers
2. The sum of two integers is 74. The larger is 26 more than twice the smaller. Find the two integers.
kompoz [17]
74=x+y is the equation at the beginning we will say that x is the smaller number and y is the larger one. Now we substitute the larger number (y) for 26+2x. Plug that into the beginning equation to get 74= x+ 26+2x. Now solve.
74=3x+26
48=3x
16=x
So we know that our smaller number is 16. To find the larger number we plug the value of the smaller number into the equation for the larger number like this.
y=26+2x
y=26+2(16)
y=26+32
y=58.
So to check our answer we can plug in both values into the beginning equation.
74=58+16
74=74.
So to sum this up the smaller number is 16 and the larger number is 58.

4 0
3 years ago
If the length of one base of a trapezoid is 5, the length of the other base is 2x + 7, and the length of the midsegment is 6x –
enyata [817]

Answer:

x = 6

Step-by-step explanation:

The midsegment of a trapezoid is the line parallel to the parallel sides of the trapezoid, which connects the midpoints of the non-parallel sides.

The length of the midsegment of the trapezoid is half the sum of the length of the parallel sides.

i.e,

Length of the midsegment = (1/2) *(Length of base1 + Length of base2)

6x - 24 = (1/2) * (5 + 2x + 7)

12x - 48 = 2x + 12

10x = 60

x=6

∴ x = 6

8 0
3 years ago
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