Answer:
For the production of 77.4 L water 90.3 L oxygen is required.
Explanation:
Given data:
Volume of oxygen required = ?
Volume of water produced = 77.4 L
Solution:
Chemical reaction equation:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
1 mole = 22.414 L
There are 6 moles of water = 6×22.414 = 134.5 L
There are 7 moles of oxygen = 7×22.414 = 156.9 L
Now we will compare the litters of water and oxygen:
H₂O : O₂
134.5 : 156.9
77.4 : 156.9/134.5×77.4 =90.3 L
So for the production of 77.4 L water 90.3 L oxygen is required.
Answer:
it's a metel
Explanation:
as far as it can conduct electricity.
it's not a metal if it can't except it it's a metalloids
