Organic: sugar
inorganic: salt
Answer:
2.9 grams.
Explanation:
- From the balanced reaction:
<em>Mg + 1/2O₂ → MgO,</em>
1.0 mole of Mg reacts with 0.5 mole of oxygen to produce 1.0 mole of MgO.
- We need to calculate the no. of moles of (1.8 g) of Mg and (6.0 g) of oxygen:
no. of moles of Mg = mass/molar mass = (1.8 g)/(24.3 g/mol) = 0.074 mol.
no. of moles of O₂ = mass/molar mass = (6.0 g)/(16.0 g/mol) = 0.375 mol.
<em>So. 0.074 mol of Mg reacts completely with (0.074/2 = 0.037 mol) of O₂ which be in excess.</em>
<em></em>
<em><u>Using cross multiplication:</u></em>
1.0 mole of Mg produce → 1.0 mol of MgO.
∴ 0.074 mol of Mg produce → 0.074 mol of MgO.
<em>∴ The amount of MgO produced = no. of moles x molar mass </em>= (0.074 mol)(40.3 g/mol) = <em>2.98 g.</em>
Answer:
Polar
Explanation:
A polar climate is a place where the climate usually has a temperature below freezing, icy, and covered in snow. These areas do not get direct heat and sunlight from the sun. Polar climates are located at the North Pole of the Arctic, and at the South Pole on the continent of Antarctica.
The law of conservation has been stated that the mass and energy has neither be created nor destroyed in a chemical reaction.
The law of conservation has been evident when there has been an equal number of atoms of each element in the chemical reaction.
<h3>Conservation law</h3><h3 />
The given equation has been assessed as follows:
The reactant has absence of hydrogen, while hydrogen has been present in the product. Thus, the reaction will not follow the law of conservation.
The number of atoms of each reactant has been different on the product and the reactant side. Thus, the reaction will not follow the law of conservation.
The reactant has the presence of carbon, while it has been absent in the reactant. Thus, the reaction will not follow the law of conservation.
The product has the presence of hydrogen, while it has been absent in the reactant. Thus, the reaction will not follow the law of conservation.
Learn more about conservation law, here:
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