let's first off notice the LCD of the denominators, hmmmm so we have denominators of 5, 3 and 13, hmmm oddly enough all those fellows are prime numbers, so the LCD will just be their product, namely 5*3*13, well, let's multiply both sides by that LCD to do away with the denominators firstly.
![\bf \cfrac{7}{5}y+\cfrac{2}{3}x=\cfrac{11}{13}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{5\cdot 3\cdot 13}}{(5\cdot 3\cdot 13)\left( \cfrac{7}{5}y+\cfrac{2}{3}x \right)}=(5\cdot 3\cdot 13)\left( \cfrac{11}{13} \right) \\\\\\ (3\cdot 13)(7y)+(5\cdot 13)(2x)=(5\cdot 3)(11)\implies 39(7y)+65(2x)=15(11) \\\\\\ 273y+130x=165\implies 273y=165-130x\implies y=\cfrac{165-130x}{273}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B7%7D%7B5%7Dy%2B%5Ccfrac%7B2%7D%7B3%7Dx%3D%5Ccfrac%7B11%7D%7B13%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bmultiplying%20both%20sides%20by%20%7D%5Cstackrel%7BLCD%7D%7B5%5Ccdot%203%5Ccdot%2013%7D%7D%7B%285%5Ccdot%203%5Ccdot%2013%29%5Cleft%28%20%5Ccfrac%7B7%7D%7B5%7Dy%2B%5Ccfrac%7B2%7D%7B3%7Dx%20%5Cright%29%7D%3D%285%5Ccdot%203%5Ccdot%2013%29%5Cleft%28%20%5Ccfrac%7B11%7D%7B13%7D%20%5Cright%29%20%5C%5C%5C%5C%5C%5C%20%283%5Ccdot%2013%29%287y%29%2B%285%5Ccdot%2013%29%282x%29%3D%285%5Ccdot%203%29%2811%29%5Cimplies%2039%287y%29%2B65%282x%29%3D15%2811%29%20%5C%5C%5C%5C%5C%5C%20273y%2B130x%3D165%5Cimplies%20273y%3D165-130x%5Cimplies%20y%3D%5Ccfrac%7B165-130x%7D%7B273%7D)
Answer:
1.55
Step-by-step explanation:
9.30/6=1.55
Answer:
1/10 chance
Step-by-step explanation:
it is a 1/5 chance to pull a 2, 1/2 chance to pull a red card.
these are the space numbers:
1, 2, 3, 4, 5.
card colors,
red, black.
there is one of each card color per number,
1, 2, 3, 4, 5,
| | | | |
V V V V V
2, 2,2, 2, 2,
so in total there should be
2 x 5 =
10.
there should be 10 cards.
it would be a 1/10 chance to pull a red 2
Hope this Helps!
and im sorry if i made a mistake :<
Answer:
![-8x+6](https://tex.z-dn.net/?f=-8x%2B6)
Step-by-step explanation:
we know that
The expression Subtract
from
is equivalent to the algebraic equation
![=(-3x+4)-(5x-2)](https://tex.z-dn.net/?f=%3D%28-3x%2B4%29-%285x-2%29)
![=-3x+4-5x+2](https://tex.z-dn.net/?f=%3D-3x%2B4-5x%2B2)
Group terms that contain the same variable
Combine like terms
![=(-3x-5x)+(4+2)](https://tex.z-dn.net/?f=%3D%28-3x-5x%29%2B%284%2B2%29)
![=(-8x)+(6)](https://tex.z-dn.net/?f=%3D%28-8x%29%2B%286%29)
![=-8x+6](https://tex.z-dn.net/?f=%3D-8x%2B6)