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mel-nik [20]
3 years ago
13

Jason had to replace the floor of a triangular portion of his dining room. The portion had a height that was twice as high as th

e base. If the total area of the portion he needed to replace was 16 square feet (16ft2),how long in feet was the base of the portion he needed to replace?
Mathematics
1 answer:
Eva8 [605]3 years ago
3 0

Answer:

4 feet

Step-by-step explanation:

We know the the area of a triangle can be represented as \frac{bh}{2}.

Since the height is twice the base, we can substitute the value 2b in as h in the expression, making it \frac{b\cdot2b}{2}. If the area is 16, we can make the equation

\frac{b\cdot2b}{2} = 16

Now to solve for b.

\frac{2b^2}{2} = 16\\\frac{2b^2}{2}\cdot2 = 16\cdot2\\\\2b^2 = 32\\\\2b^2\div2 = 32\div2\\\\b^2 = 16\\\\b=4

Hope this helped!

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