Jason had to replace the floor of a triangular portion of his dining room. The portion had a height that was twice as high as th
e base. If the total area of the portion he needed to replace was 16 square feet (16ft2),how long in feet was the base of the portion he needed to replace?
You can use the cosine law with the formula: a^2 = b^2 + c^2 - 2*b*c*cosA With a = 5, b = 5, c = 7, 7^2 = 5^2 + 5^2 - 2*5*7*cosA 49 = 25 + 25 - 70*cosA 70*cosA = 25 + 25 - 49 70*cosA = 1 cosA = 1/70 A = arccos (1/70) = 89.18 deg = 89 deg