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4 years ago

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Jason had to replace the floor of a triangular portion of his dining room. The portion had a height that was twice as high as th

e base. If the total area of the portion he needed to replace was 16 square feet (16ft2),how long in feet was the base of the portion he needed to replace?

1 answer:

Eva8 [605]4 years ago

3 0

Answer:

4 feet

Step-by-step explanation:

We know the the area of a triangle can be represented as $\frac{bh}{2}$ .

Since the height is twice the base, we can substitute the value $2b$ in as $h$ in the expression, making it $\frac{b\cdot2b}{2}$ . If the area is 16, we can make the equation

$\frac{b\cdot2b}{2} = 16$

Now to solve for b.

$\frac{2b^2}{2} = 16\\\frac{2b^2}{2}\cdot2 = 16\cdot2\\\\2b^2 = 32\\\\2b^2\div2 = 32\div2\\\\b^2 = 16\\\\b=4$

Hope this helped!

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