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mart [117]
3 years ago
14

Please Evaluate 8(12+7-9)

Mathematics
2 answers:
Anestetic [448]3 years ago
5 0
Distribute 8 to all of your numbers inside of the parentheses first, and then add and subtract all of your numbers together to get 80.
8(12+7-9)
96+56-72
152-72
80

OR...

Do what's inside the parentheses first, which equals 10. Then multiply that by 8 and get the same answer. 80. 
Drupady [299]3 years ago
3 0
You distribute 8 into all the numbers which would be 8×12, 8×7, and 8×9. So the answer would be 96+56-72. Hope that helps.
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What is 15% of 60? create a model to prove your answer. in equivalent fractions
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3 years ago
If the p-value = 0.008, what conclusion can be drawn?
Paladinen [302]

Answer: option A is correct, we accept the null hypothesis.

Step-by-step explanation:

At a 5% level of significance, p = 0.05, therefore when p < 0.05, accept the null hypothesis (H°) and reject the alternative hypothesis (H¡). When p > 0.05, we reject the null hypothesis (H°) and accept the alternative hypothesis (H¡)

Given the p-value to be 0.008, this is less than the 5% threshold, that is, 0.05, hence we accept the null hypothesis.

3 0
3 years ago
On Halloween, a man presents a child with a bowl containing eight different pieces of candy. He tells her that she may have thre
likoan [24]

Answer:

56 choices

Step-by-step explanation:

We know that we'll have to solve this problem with a permutation or a combination, but which one do we use? The answer is a combination because the order in which the child picks the candy <u><em>does not</em></u> matter.

To further demonstrate this, imagine I have 4 pieces of candy labeled A, B, C, and D. I could choose A, then C, then B or I could choose C, then B, then A, but in the end, I still have the same pieces, regardless of what order I pick them in. I hope that helps to understand why this problem will be solved with a combination.

Anyways, back to the solving! Remember that the combination formula is

_nC_r=\frac{n!}{r!(n-r)!}, where n is the number of objects in the sample (the number of objects you choose from) and r is the number of objects that are to be chosen.

In this case, n=8 and r=3. Substituting these values into the formula gives us:

_8C_3=\frac{8!}{3!5!}

= \frac{8*7*6*5*4*3*2*1}{3*2*1*5*4*3*2*1} (Expand the factorials)

=\frac{8*7*6}{3*2*1} (Cancel out 5*4*3*2*1)

=\frac{8*7*6}{6} (Evaluate denominator)

=8*7 (Cancel out 6)

=56

Therefore, the child has \bf56 different ways to pick the candies. Hope this helps!

3 0
3 years ago
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