
the denominator cannot be zero, because the division by zero is not defined, therefore:
![\begin{gathered} x^2-9=0 \\ \text{Solving for x:} \\ x^2=9 \\ \sqrt[]{x^2}=\sqrt[]{9} \\ x=\pm3 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%5E2-9%3D0%20%5C%5C%20%5Ctext%7BSolving%20for%20x%3A%7D%20%5C%5C%20x%5E2%3D9%20%5C%5C%20%5Csqrt%5B%5D%7Bx%5E2%7D%3D%5Csqrt%5B%5D%7B9%7D%20%5C%5C%20x%3D%5Cpm3%20%5Cend%7Bgathered%7D)
Therefore the domain of (f o g)(x) is:
Answer:
Ok so the area of the frame is 18*12 = 216cm^2
Let’s suppose the width of the frame is x
The total area (painting and frame) is (2x+18)(2x+12) and this is equal to 432
4x^2 + 60x + 216 = 432
4x^2 + 60x - 216 = 0
x^2 + 15x - 54 = 0
(x+18)(x-3) = 0
Therefore x = {-18,3}
Since width of the frame has to be positive, the width has to be 3cm Step-
i hope i helped!
Answer:
2
Step-by-step explanation:
24/ 11 = 2 2/11
so, we have 2 and 2/11
11x2 = 22 + 2 = 24
Answer:
the student ate 1/2
Step-by-step explanation: