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3 years ago

Help me solve the equations, please. Very urgent!!

Mathematics

2 answers:

user100 [1]3 years ago

8 0

<h3>- - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - </h3>

➷ 847) You need to cross multiply

Multiply both sides by (x - 7) and 3

This is what you should get:

$3x- 42 = 2x - 14$

Now we just need to get like terms on the same side.

Add 42 to both sides and subtract 2x from both also

Now you get this:

$x = 28$

848) It's the same principle in this one too.

Multiply both sides by (x - 13) and 11

You should get:

$11x - 132 = 12x - 156$

Subtract 11x from both sides and add 156 also

Now you get:

$x = 24$

849) Multiply both sides by x

You should get:

$x - 12 = -4x$

Add 4x to both sides and add 12 also:

$5x = 12$

Divide both sides by 5

$x = 2.4$

850) Multiply both sides by x

You should get:

$x-12 = 4x$

Subtract x from both sides:

$3x = -12$

Divide both sides by 3:

$x=-4$

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ Hannah ♡

elixir [45]3 years ago

3 0

Answer:

the answers are below the solution.

Step-by-step explanation:

847. x-14/x-7 = 2/3

cross multiply

3(x - 14) = 2(x - 7)

open the bracket

3x - 42 = 2x - 14

combine the like terms

3x - 2x = -14 +42

x = -28

848. x - 12/x - 13 = 12/11

cross multiply

11(x - 12) = 12(x - 13)

11x - 132 = 12x - 156

combine the like terms

11x - 12x = -156 +132

-x = -24

divide by -1

-x/-1 = -24/-1

x = 24

849. x - 12/x = -4

first make x - 12/x a single fraction

x-12/x = -4

cross multiply

x - 12 = -4x

combine the like terms

-12 = -4x - x

-12 = -5x

divide by -5

-12/-5 = -5x/-5

2.4 = x

x = 2.4

850. x - 12/x = 4

make x - 12/x a single fraction

x-12/x = 4

cross multiply

x - 12 =4x

combine the like terms

-12 = 4x - x

-12 = 3x

divide by 3

-12/3 = 3x/3

-4 = x

x = -4

I hope this will help

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andrew-mc [135]

Answer:

The area function is

$A=\frac{135}{2}x-\frac{9}{2}x^2$ .

The domain and range of A is $(0,15m)$ and $(0, 253.125 m^2]$ .

Step-by-step explanation:

The given length of fencing is $90 m$ .

Let the length and width of each pen be $x$ and $y$ respectively as shown in the figure.

As there are 3 pens, so, the total area,

$A= 3 xy \;\cdots (i)$

From the figure the total length of fencing is $6x+4y$ .

Here, for a significant area for the animals, $x>0$ as well as $y>0$ as $x$ and $y$ are the sides of ben.

From the given value:

$6x+4y=90\;\cdots (ii)$

$\Rightarrow y=\frac {45}{2}-\frac{3x}{2}$

Now, from equation (i)

$A=3x\left(\frac {45}{2}-\frac{3x}{2}\right)$

$\Rightarrow A=\frac{135}{2}x-\frac{9}{2}x^2\;\cdots (iii)$

This is the required area function in the terms of variable $x$ .

For the domain of area function, from equation (ii)

$x=15-\frac{2y}{3}$

$\Rightarrow x$ [as y>0]

So, the domain of area function is $(0,15m)$ .

For the range of area function:

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$\Rightarrow A>0$

Now, differentiate the area function with respect to $x$ .

$\frac {dA}{dx}=\frac{135}{2}-9x$

Equate $\frac {dA}{dx}$ to zero to get the extremum point.

$\frac {dA}{dx}=0$

$\Rightarrow \frac{135}{2}-9x=0$

$\Rightarrow x=\frac{15}{2}$

Check this point by double differentiation

$\frac {d^2A}{dx^2}=-9$

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$A=\frac{135}{2}\times \frac {15}{2}-\frac{9}{2}\times \left(\frac {15}{2}\right)^2$

$\Rightarrow A=253.125 m^2$

Hence, the range of area function is $(0, 253.125 m^2]$ .

4 0

3 years ago

Please see attached image and help with these absolute value problems - thank you

Novay_Z [31]

Answer:

{-infinity, infinity}

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Step-by-step explanation:

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This is always true so x can be and real number

{-infinity, infinity}

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Divide by -2

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3 years ago

Jack had 3 bags of golf balls with b balls in each bag; then his friend gave him 6 more golf balls. How many golf balls does Jac

earnstyle [38]

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3 years ago

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An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

andrey2020 [161]

Answer:

The probability that A selects the first red ball is 0.5833.

Step-by-step explanation:

Given : An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

To find : What is the probability that A selects the first red ball?

Solution :

A wins if the first red ball is drawn 1st,3rd,5th or 7th.

A red ball drawn first, there are $E(1)= ^9C_2$ places in which the other 2 red balls can be placed.

A red ball drawn third, there are $E(3)= ^7C_2$ places in which the other 2 red balls can be placed.

A red ball drawn fifth, there are $E(5)= ^5C_2$ places in which the other 2 red balls can be placed.

A red ball drawn seventh, there are $E(7)= ^3C_2$ places in which the other 2 red balls can be placed.

The total number of total event is $S= ^{10}C_3$

The probability that A selects the first red ball is

$P(A \text{wins})=\frac{(^9C_2)+(^7C_2)+(^5C_2)+(^3C_2)}{^{10}C_3}$

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$P(A \text{wins})=\frac{70}{120}$

$P(A \text{wins})=0.5833$

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3 years ago

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RoseWind [281]

From figure 1: -

From figure 2: 12

From figure 3: 6

From figure 4: -12

From figure 5: -2

Step-by-step explanation:

We need to solve the equation $4k-6=-2k-16-2$ for k.

Solving:

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So, the options to be selected are:

From figure 1: -

From figure 2: 12

From figure 3: 6

From figure 4: -12

From figure 5: -2

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