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2 years ago

If 16*x=1/64, find the value of x

Mathematics

2 answers:

blondinia [14]2 years ago

7 0

Answer:

x = - $\frac{3}{2}$

Step-by-step explanation:

Assuming you mean

$16^{x}$ = $\frac{1}{64}$

note that 16 = 4² and 64 = 4³ , so

$(4^{2} )^{x}$ = $\frac{1}{4^{3} }$

$4^{2x}$ = $4^{-3}$

Since the bases on both sides are equal, both 4, then equate exponents

2x = - 3 ( divide both sides by 2 )

x = - $\frac{3}{2}$ ( = - 1.5 )

Stels [109]2 years ago

6 0

Answer:

I think it is x=1/1024 not sure but try it

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The error is in the resolution of the proportion. In fact, the initial proportion is correct:

$\frac{5}{3.5}=\frac{12}{x}$

where x is the total cost. However, the following step of the resolution is wrong. In fact, the correct resolution is the following:

- Multiplying by x on both sides:

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3 years ago

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2 years ago

PLS HELP WITH ALGEBRA

pantera1 [17]

Answer:

1. 4x(x^2+5x+4)

2. 2x^2(6x^2+13x-8)

3. 2(5x^2+24x-5)

Step-by-step explanation:

The common factor between all the monomials is 4x, so we divide each by 4x.

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2 years ago

pdf A group of college students are volunteering for Help the Homeless during their spring break. They are putting the finishing

Svetlanka [38]

Answer:

the equation would be

t = tM/(1+tM/tJ) = tM*tJ/(tM+tJ)

and the time required for both to paint the room when they work together is t= 4.44 hours

Step-by-step explanation:

For Jorge

Painted surface of the room = velocity of painting of Jorge * time required for Jorge to paint the room

For Maria

Painted surface of the room = velocity of painting of Maria* time required for Maria to paint the room

then

velocity of painting of Jorge * time required for Jorge to paint the room= velocity of painting of Maria* time required for Maria to paint the room

velocity of painting of Jorge =velocity of painting of Maria* time required for Maria to paint the room/time required for Jorge to paint the room ) = velocity of painting of Maria* (8 hours/10 hours)= 0.8*velocity of painting of Maria

thus Jorge paints 20% slower than Maria

Then if they will paint together i will assign them different portions of the room so they do not disturb each other for painting ( work in parallel) and assign this portions so they end at the same time ( so there is no dead time and i minimise the time required)

then

Surface painted of Jorge = velocity of painting of Jorge * time required for both to paint the room

Surface painted of Maria = velocity of painting of Maria * time required for both to paint the room

such that

Surface painted of Jorge + Surface painted of Maria= Painted surface of the room

replacing the equations

velocity of painting of Jorge * time required for both to paint the room + velocity of painting of Maria * time required for both to paint the room = velocity of painting of Maria* time required for Maria to paint the room

since velocity of painting of Jorge= 0.8*velocity of painting of Maria

0.8*velocity of painting of Maria * time required for both to paint the room + velocity of painting of Maria * time required for both to paint the room = velocity of painting of Maria* time required for Maria to paint the room

thus

1.8* time required for both to paint the room= time required for Maria to paint the room

time required for both to paint the room = time required for Maria to paint the room/1.8 = 8 hours/ 1.8 = 4.44 hours

the equation would be

t = tM/(1+tM/tJ) = tM*tJ/(tM+tJ)

1/t= 1/tM + 1/tJ (work in parallel)

where

t = time required for both to paint the room

tM = time required for Maria to paint the room

tJ = time required for Jorge to paint the room

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