If z = 3x2 + y2 and (x, y) changes from (1, 1) to (0.95, 0.9), compare the values of δz and dz. (round your answers to four deci
1 answer:
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Answer:
a₆ = 12
Step-by-step explanation:
The nth term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given a₂ = 5 and a₁₀ = 19 , then
a₁ + d = 5 → (1)
a₁ + 9d = 19 → (2)
Subtract (1) from (2) term by term to eliminate a₁
8d = 14 ( divide both sides by 8 )
d = 1.75
Substitute d = 1.75 into (1)
a₁ + 1.75 = 5 ( subtract 1.75 from both sides )
a₁ = 3.25
Then
a₆ = 3.25 + 5(1.75) = 3.25 + 8.75 = 12
Answer:
BC = 11
Step-by-step explanation:
using the sine ratio in the right triangle and the exact value
sin45° = , then
sin 45° = =
=
=
( cross- multiply )
BC = 11