<u><em>Answer:</em></u>
SAS
<u><em>Explanation:</em></u>
<u>Before solving the problem, let's define each of the given theorems:</u>
<u>1- SSS (side-side-side):</u> This theorem is valid when the three sides of the first triangle are congruent to the corresponding three sides in the second triangle
<u>2- SAS (side-angle-side):</u> This theorem is valid when two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle
<u>3- ASA (angle-side-angle):</u> This theorem is valid when two angles and the included side between them in the first triangle are congruent to the corresponding two angles and the included side between them in the second triangle
<u>4- AAS (angle-angle-side):</u> This theorem is valid when two angles and a side that is not included between them in the first triangle are congruent to the corresponding two angles and a side that is not included between them in the second triangle
<u>Now, let's check the given triangles:</u>
We can note that the two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle
This means that the two triangles are congruent by <u>SAS</u> theorem
Hope this helps :)
8x + 7 = 5
A "product" is the result of a multiplication operation. So the product of a number, ( which we will call x,) and 8 would be 8x. (Or 8*"x" number) 7 more than that product would be 8x + 7 = 5
Hope that this helps!
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10h + 14k = 2(5h+7k)
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Answer: 32/24
Step-by-step explanation:
On a field trip, there are 8 adults and 24 students. What is the ratio of students to the total number of people on the field trip?
32 is the total amount of people on the field trip, 24 students
32/24 would be the correct ratio.
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<span>Assume 11^10 - 1 = 0 (mod 100) (i.e. 11^10 - 1 is divisible by 100).
11^10 - 1 = 0 (mod 100)
11^10 = 1 (mod 100)
(11^2)^5 = 1 (mod 100)
(121)^5 = 1 (mod 100)
(21)^5 = 1 (mod 100) [the remainder of 121 divided by 100 is 21]
(21^2)^2(21) = 1 (mod 100)
(41)^2(21) = 1 (mod 100)
81(21) = 1 (mod 100)
1701 = 1 (mod 100)
∴ 11^10 - 1 is divisible by 100.</span>
