Number 5 is c, number 6 is 'a'
Answer:
You would start with 00.-6 and stop a-5954
Step-by-step explanation:
Answer:
I'd say about 30 minutes away
Step-by-step explanation:
Answer:
125
Step-by-step explanation:
f(1)= the first time (32,000)
n= 9
r= .5 (each term is being mulitplied by .5 to get the next one
We have
32,000*(.5)^(9-1)
32,000*(.5)^8
=125
Answer:
None of these.
Step-by-step explanation:
Let's assume we are trying to figure out if (x-6) is a factor. We got the quotient (x^2+6) and the remainder 13 according to the problem. So we know (x-6) is not a factor because the remainder wasn't zero.
Let's assume we are trying to figure out if (x^2+6) is a factor. The quotient is (x-6) and the remainder is 13 according to the problem. So we know (x^2+6) is not a factor because the remainder wasn't zero.
In order for 13 to be a factor of P, all the terms of P must be divisible by 13. That just means you can reduce it to a form that is not a fraction.
If we look at the first term x^3 and we divide it by 13 we get
we cannot reduce it so it is not a fraction so 13 is not a factor of P
None of these is the right option.