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Answer:
A) (1 s, 2.3 s)
B) (-4 m/s², 3.8 m/s²)
Step-by-step explanation:
The car's position which is the distance is given by the equation;
s(t) = t³ - 5t² + 7t
A) Velocity is the first derivative of the distance. Thus;
v(t) = ds/dt = 3t² - 10t + 7
At v = 0, we have;
3t² - 10t + 7 = 0
Using quadratic formula, we have;
t = 1 and t = 2.3
Thus, time at velocity of 0 is t = (1 s, 2.3 s)
B) acceleration is the derivative of the velocity. Thus;
a(t) = dV/dt = 6t - 10
At velocity of 0, we got t = 1 and t = 2.3
Thus;
a(1) = 6(1) - 10 = -4 m/s²
a(2.3) = 6(2.3) - 10 = 3.8 m/s
Thus, a(t) at v = 0 gives; (-4 m/s², 3.8 m/s²)
Answer:the answers is 75.000
Step-by-step explanation:
Answer:
So the decay percentage rate is of 70.8%
Step-by-step explanation:
An exponentil function has the following format:

In which c is a constant.
If a>1, we have that a = 1 + r and r is the growth rate.
If a<1, we have that a = 1 - r and r is the decay rate.
In this problem:
a = 0.292
A is lesser than 1, so r is the decay rate.
1 - r = 0.292
r = 1 - 0.292
r = 0.708
So the decay percentage rate is of 70.8%