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horrorfan [7]
2 years ago
7

Last month, Ed ate 9 apples, 5 bananas, 4 peaches, and 7 oranges. Find the ratio of the bananas to the total number of fruit, th

en explain it's meaning
Please help! :(
Mathematics
1 answer:
Tju [1.3M]2 years ago
5 0

Answer: 5 bananas to 25 fruits

Step-by-step explanation: its kinda hard for me to explain 0.0

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Five hundred plus five hundred fifty
JulsSmile [24]

Answer:

1,050

Step-by-step explanation:

500

+

550

=

1,050 You add the numbers getting your total

4 0
3 years ago
If $500 is shared in the ratio 2:3:9 then the difference between the largest and the smallest shares is
madreJ [45]

Answer:

$250

Step-by-step explanation:

Total parts:

2+3+9 = 14

500/14 = 250/7

2×250/7 : 3×250/7 : 9×250/7

500/7 : 750/7 : 2250/7

The largest share is 2250/7, the smallest share is 500/7.

Find the difference.

2250/7 - 500/7 = 250

8 0
3 years ago
Read 2 more answers
Pls help
mr Goodwill [35]
It's a because 5 divided by 9 equals .555555555555556. The 6 is just from rounding the number. Otherwise the five would go on forever. The bar means go on forever. So it .5 with a bat over the 5
4 0
3 years ago
What is the Difference Between a 16-Ounce Brick and a Carpenter?
Andrew [12]

One weighs a pound, and the other pounds away!

4 0
3 years ago
Read 2 more answers
A rock was thrown from the top of a cliff such that its distance above sea level was given by s(t)= at² + bt + c, where t is the
frutty [35]

Answer:

<h2>a) a = -3, b = 18, c = 48; </h2><h2>s(t) = -3t²+18t+48</h2><h2>b) 48m</h2><h2>c) 8secs</h2>

Step-by-step explanation:

The question is incomplete. Here is the complete question.

'A rock was thrown from the top of a cliff such that its distance above sea level was given by s(t)=at²+bt+c, where t is the time in seconds after the rock was released. After 1 second the rock was 63 m above sea level, after 2 seconds 72 m, and after 7 seconds 27 m. a. Find a, b and c and hence an expression for s(t). b. Find the height of the cliff. c. Find the time taken for the rock to reach sea level.'

Given the equation of the distance modelled as s(t)=at²+bt+c

If after 1 second the rock was 63 m, then 63 = a+b+c

If after 2 seconds, the distance was 72 m then 72 = 4a+2b+c

Also if after 7 seconds, the distance is 27 m, then 27 = 49a+7b+c

i) Solving the 3 equations simultaneously to get a, b and c we have;

a+b+c = 63 ... 1

4a+2b+c = 72 ...2

49a+7b+c = 27 ...3

Subtracting 2 from 1 and 3 from 2 we will generate 2 new equations as shown;

eqn 2- eqn1: 3a + b = 9...4

eqn 3- eqn 2: 45a + 5b = -45

eqn 3- eqn 2: 9a+b = -9 ... 5

solving 4 and 5 simultaneously

3a + b = 9 ...4

9a+b = -9 ... 5  

Taking the difference of 4 and 5 we have

6a - -9-9

6a = -18

a = -3

substituting a = -3 into equation 4 to get b we have;

3(-3)+b = 9

-9 + b = 9

b = 9+9

b = 18

substituting a = -3 and b = 18 into equation 1 to get c we have;

-3+18+c = 63

15+c = 63

c = 48

a = -3, b= 18 and c = 48

The distance function will be s(t) = -3t²+18t+48

ii) If the height of the cliff is modelled by the equation  s(t)=at²+bt+c

The height of the cliff is at when t = 0

s(0) = -3(0)²+18(0)+48

s(0) = 48m

The height of the cliff is 48m

iii) At the sea level, the height of the rock will be 0m, substituting this into the modeled equation for the height to get the time we have;

s(t)=at²+bt+c

0 = -3t²+18t+48

3t²-18t-48 = 0

t² - 6t - 16 =0

t² - 8t+2t - 16 = 0

t(t-8)+2(t-8) = 0

(t+2)(t-8) = 0

t = -2 or 8

Taking the positive value of the time, t = 8secs

Time taken for the rock to reach sea level is 8secs

7 0
3 years ago
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