Consider the diagram shown and answer the following questions; the radius of this circle is 6 inches:
1 answer:
Refer to the figure shown below.
Part 1
Triangles VPU and SPU are congruent because of SSA. Therefore,
∠TUV = ∠TUS = 39°.
Because angles in quadrilateral PVUS sum to 360°, therefore
The Central ∠VPS = 360 -(90+39+39+90) = 102°.
The measure of arc VTS = ∠VPS = 102°.
Part 2
We know that line segments PO = PS = PT = 6 in (radius).
Because TO is a diameter, ∠TMO = 90°.
From the indicated right triangles ΔUPV, ΔUPS, ΔMOT, we can calculate the lengths of PU, US, UV, MT and MO.
Part 3
Angles in a triangle sum to 90°. Because ∠MOP = 49°, therefore
∠MTO = 90 - 49 = 41°.
∠VPU = ∠SPU = 90 - 39 = 51°.
Part 1
Triangles VPU and SPU are congruent because of SSA. Therefore,
∠TUV = ∠TUS = 39°.
Because angles in quadrilateral PVUS sum to 360°, therefore
The Central ∠VPS = 360 -(90+39+39+90) = 102°.
The measure of arc VTS = ∠VPS = 102°.
Part 2
We know that line segments PO = PS = PT = 6 in (radius).
Because TO is a diameter, ∠TMO = 90°.
From the indicated right triangles ΔUPV, ΔUPS, ΔMOT, we can calculate the lengths of PU, US, UV, MT and MO.
Part 3
Angles in a triangle sum to 90°. Because ∠MOP = 49°, therefore
∠MTO = 90 - 49 = 41°.
∠VPU = ∠SPU = 90 - 39 = 51°.
You might be interested in
We are given dimensions of model and actual figure.
model: 9.5cm actual : 30.5m.
We need to find the length of actual shape for the scale factor 5cm.
Let us assume actual length be x m.
Let us set a proportion now.
<h3>5 : x = 9.5 : 30.5</h3>Let us convert proportion into fractions.
On cross multiplying, we get
9.5x = 5× 30.5
9.5x = 152.5.
On dividing both sides by 9.5, we get
x=16.05.
<h3>Therefore, the scale factor for a model is 5cm= 16.05 m.</h3>