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kkurt [141]
3 years ago
7

A ball is thrown upward from the top of a building. The function below shows the height of the ball in relation to sea level, f(

t), in feet, at different times, t, in seconds: f(t) = −16t2 + 32t + 384 The average rate of change of f(t) from t = 4 seconds to t = 6 seconds is _____ feet per second
Mathematics
2 answers:
SpyIntel [72]3 years ago
5 0

It is given in the question that,

A ball is thrown upward from the top of a building. The function below shows the height of the ball in relation to sea level, f(t), in feet, at different times, t, in seconds:

f(t) = −16t^2 + 32t + 384

At t=4seconds,

we will get

f(4) = -16(4)^2+32(4) +384 = $256

At t=6 seconds, we will get

f(6)= -16(6)^2 +32(6)+384 =0

THerefore, average rate of change is

\frac{f(6)-f(4)}{6-4} = \frac{0-256}{2-0} = -128feet/second

And that's the required answer .

vovangra [49]3 years ago
4 0
The answer is -128
-16(6)² + 32(6) + 384 = 0
-16(4)² + 32(4) + 384 = 256
0 - 256/6 - 4 = -128

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