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suter [353]
2 years ago
15

The formula for the axis of symmetry of a quadratic equation in standard form is

Mathematics
1 answer:
stepan [7]2 years ago
6 0

Answer:

C. b=-2ax

Step-by-step explanation:

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Using the function p(x)=4x-3 what is p(5)
12345 [234]

Answer:

p(5) = 17

Step-by-step explanation:

p(x) = 4x - 3

p(5) = 4(5) - 3

     = 20 - 3

     = 17

8 0
3 years ago
What is the area of a circle with a diameter of 6x? (Use 3.14 for R
kykrilka [37]
3.14=r
d= 3.14*2
d= 6.28

Area = 3.14*(6..28)^2
=3.14*39.43

Area = 123.83
3 0
3 years ago
I WILL GIVE BRAINlIEST TO WHOEVER CAN ANSWER ALL THE QUESTIONS!!
serg [7]

Answer:

There is no formula for this.

5 0
2 years ago
Read 2 more answers
a bookcase is to be constructed as shown in the figure below. the height of the bookcase is 2 feet longer than the length of a s
In-s [12.5K]

The length of the shelf is 10 feet while its height is 10 feet.

<h3>Equation</h3>

Equation is an expression used to show the relationship between the sides and angles of a right angled triangle.

Let x represent the shelf length and y represent the shelf height.

The height of the bookcase is 2 feet longer than the length of a shelf. hence:

  • y = x + 2
  • -x + y = 2   (1)

Also, 22 feet of lumber is available:

  • x + y = 22   (2)

From equation 1 and 2:

y = 12, x = 10

The length of the shelf is 10 feet while its height is 10 feet.

Find out more on equation at: brainly.com/question/13763238

4 0
2 years ago
Please help if you know how to do Similarity in Geometry!!
Marizza181 [45]

2. TU, UV and TV are mid-segments

3. Definition of mid-segment

4. Division property of equality

6. SSS similarity theorem

Solution:

Step 1: Given

T is the midpoint of QR.

U is the midpoint of QS.

V is the midpoint of RS.

Step 2: Mid-segments connects midpoints of opposite sides.

TU, UV and TV are mid-segments.

Step 3: By definition of mid-segment

A triangle mid-segment is parallel to the third side of the triangle and is half of the length of the third side.

T U=\frac{1}{2} R S, {U V}=\frac{1}{2} {Q} R and V T=\frac{1}{2} S Q

Step 4: By division property of equality

Divide first segment by RS, second segment by QR and third segment by SQ.

$\frac{T U}{R S}=\frac{1}{2}, \ \frac{U V}{Q R}=\frac{1}{2},  \ \frac{V T}{S Q}=\frac{1}{2}

Step 5: By transitive property

$\frac{T U}{R S}=\frac{U V}{Q R}=\frac{V T}{S Q}

Step 6: From the above steps, the sides of the triangle are congruent.

By SSS similarity theorem,

\Delta \text { QRS } \sim \Delta \text { VUT }

Hence proved.

3 0
3 years ago
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