Question

You are designing a rectangular enclosure with 2 rectangular sections separated by parallel walls. The interior wall has a length of 30 feet and the area of the enclosure is 1800 ft2. What amount of fencing is required for this project?

Answer 1

Answer:

$P = 3L + 4W= 3*30 ft + 4*30 ft = 210 ft$

So then is required at least 210 ft in order to satisfy the conditions.

Step-by-step explanation:

For this case we can assume that the rectangular enclosure is on the figure attached.

The perimeter on this case is given by:

$P = 3L + 4W$

We know that the total area is $1800ft^2$ and the total area is given this formula:

$A= 2L W$

Because we have two identical rectangular pieces.

And we can find the value for W like this:

$W = \frac{A}{2L} =\frac{1800 ft^2}{2*30 ft}= 30ft$

And then we can find the perimeter like this:

$P = 3L + 4W= 3*30 ft + 4*30 ft = 210 ft$

So then is required at least 210 ft in order to satisfy the conditions.