Question

5+4x" alt="\sqrt{16x^{2} -37x-2 }=4x" align="absmiddle" class="latex-formula">

solve for me plz with explanation

Answer 1

Answer:

Step-by-step explanation:

$\sqrt{16x^2-37x-2} =4x-5\\squaring~ both~sides\\16x^2-37x-2=16x^2-40x+25 ~[(a-b)^2=a^2-2ab+b^2]\\16x^2-37x-2-16x^2+40x-25=0\\3x-27=0\\3(x-9)=0\\x-9=0\\x=9$