Answer:
Answer 2.
Step-by-step explanation:
4 CDs for $60 vs 6 CDs for $25?
At CD Express you'll spend $240 while only spending $150 at Nuse Place.
The ways that zero growth stock valuation can affect business operations is that:
- When zero-growth model states that the dividend is at the same rate, it shows that one has no measure of growth in terms of dividends. This therefore shows that stock price is equal to the annual dividends and divided also by the needed rate of return.
<h3>What ways does constant stock valuation affect business operations?</h3>
The Constant stock valuation is known to be a kind of share evaluation as it states that the dividends paid by a firm will consistently increase at a constant growth rate.
This will help one to know especially investors on how to set or know the fair price that one needs to pay for a stock on daily basis today by due to future dividend payments.
The overall statement is that stock value affect one's business operations as the company's stock price is one that shows an investor perception of their capability to get profit and also if they can grow their profits in terms of future times.
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Answer:
6t = c
Step-by-step explanation:
If there are six chairs per table, you need to find how many tables there are, after that, then you can find how many chairs you need.
Answer:
q = -13
Step-by-step explanation:
The given equation is:

Taking 2 as common from left hand side, we get:
![2(x^{2}-4x)=5\\\\2[x^{2} - 2(x)(2)]=5](https://tex.z-dn.net/?f=2%28x%5E%7B2%7D-4x%29%3D5%5C%5C%5C%5C2%5Bx%5E%7B2%7D%20-%202%28x%29%282%29%5D%3D5)
The square of difference is written as:
Equation 1
If we compare the given equation from previous step to formula in Equation 1, we note that we have square of first term(x), twice the product of 1st term(x) and second term(2) and the square of second term(2) is missing. So in order to complete the square we need to add and subtract square of 2 to right hand side. i.e.
![2[x^{2}-2(x)(2)+(2)^2-(2)^{2}]=5\\\\ 2[x^{2}-2(x)(2)+(2)^2]-2(2)^{2}=5\\\\ 2(x-2)^{2}-2(4)=5\\\\ 2(x-2)^2-8=5\\\\ 2(x-2)^{2}-8-5=0\\\\ 2(x-2)^{2}-13=0](https://tex.z-dn.net/?f=2%5Bx%5E%7B2%7D-2%28x%29%282%29%2B%282%29%5E2-%282%29%5E%7B2%7D%5D%3D5%5C%5C%5C%5C%202%5Bx%5E%7B2%7D-2%28x%29%282%29%2B%282%29%5E2%5D-2%282%29%5E%7B2%7D%3D5%5C%5C%5C%5C%202%28x-2%29%5E%7B2%7D-2%284%29%3D5%5C%5C%5C%5C%202%28x-2%29%5E2-8%3D5%5C%5C%5C%5C%202%28x-2%29%5E%7B2%7D-8-5%3D0%5C%5C%5C%5C%202%28x-2%29%5E%7B2%7D-13%3D0)
Comparing the above equation with the given equation:
, we can say:
p = 2 and q= -13