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nevsk [136]
3 years ago
6

Heterotrophs select one:

Biology
1 answer:
Talja [164]3 years ago
8 0
B is the only answer that correctly correlates to the question. Heterotrophs are organism that are not able to produce their own source of food. To acquire food, they depend on the organic molecules produced by producers.
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It would be all of the above
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All organisms have adaptations for their environment. Identify two adaptations that could be useful for organisms that live in a
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Some animals in the desert don't need to drink water, yet things in the tundra need water

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How many different populations live in the pond?​
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Depends on the environment, climate and etc

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to encourage a yellow pigmentation, micrococcus luteus has to be incubated at a. 0 degrees C b. 25 degree C c. 37 degree C d. 10
eduard

Answer:

C. 37 degree C

Explanation:

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Due to the Bacteria thriving well in the body of humans, the optimal incubation rate is usually 37 degree C which is the same body temperature of humans and it aids the yellow pigmentation of the bacteria

6 0
4 years ago
2.86 A ball is dropped from rest from the top of a cliff that is 24 m high. From ground level, a second ball is thrown straight
Rashid [163]

Answer:

Distance Below the top = 6,02 m

Explanation:

To get the Final velocity of the first ball (that will be the intial velocity of the second) you need to solve the kinematic equation for Velocity:

(1) V_{1f} =V_{1O}  - gt

As the ball is dropped from rest V_{1O} = 0, so:

(2) V_{1f} = - gt

Note that the velocity is going to be negative as the ball is going down. To get the time it would take the ball to reach de base you can use the kinematic equation for position:

(3) h_{1} = h_{1O} + V_{1O} *t - \frac{1}{2} gt^{2}

We need the answer when h=0, and from the initial conditions V_{1O} = 0, h_{1O} = 24m, you get:

(4) 24m = \frac{1}{2} gt_{1f}^{2}

Solving for t, with 9,8\frac{m}{s^{2}} and :

(5) t_{1f} = \sqrt{\frac{24m*2}{g} } = 2,21 s

Replacing this time in (2), the final velocity is:

(6) V_{1f} = -21,66  \frac{m}{s}

So the initial velocity of ball 2 is equial to this but oppossite in direction so: V_{2O}= -V_{1f} = 21,66  \frac{m}{s}

The general position equation for ball 2 is (considering h_{2O} = 0 :

(7) h_{2} = V_{2O} *t - \frac{1}{2} gt^{2}

They cross paths when h_{1}=h_{2} so:

(8) h_{1O} - \frac{1}{2} gt^{2} = V_{2O} *t - \frac{1}{2} gt^{2}

Rearranging:

(9) t_{cross} =\frac{h_{1O}}{V_{2O} }

Replacing values:

t_{cross} = 1,108 s

To get the absolute position replace t_{cross} on equation (3) or (7):

h_{cross} = 17,98 m

To get it below the top of te cliff:

h_{cross, from above} = 24 m - 17,98 m

h_{cross, from above} = 6,02 m

3 0
4 years ago
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