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Jet001 [13]
3 years ago
5

What’s the answer to 3 squared-6(3)-5

Mathematics
1 answer:
Ganezh [65]3 years ago
7 0
The answer should be -14
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There are 8 students on the minibus. Five of the students or boys. What fraction of the students are boys
blagie [28]
The fraction would be 5/8
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I want to know the equation of the line
Fofino [41]
\frac{rise}{run} = \frac{-1}{4}
The equation is y = -\frac{1}{4}x + (-6)


6 0
3 years ago
At a certain time of day, a 5 foot tall man has an 8 foot shadow. If a tree is 20 feet tall, what is the distance between the tr
Leto [7]
If they're asking the distance between the tree and the man's shadow, that would be 12ft and if they're asking the distance between the tree and the actually man, that would be 15ft :).
5 0
4 years ago
. An individual wishes to invest $5000 over the next year in two types of investment: Investment A yields 5%, and investment B y
tresset_1 [31]

Answer:

The amount invested at Investment A must be greater than or equal to $2,750

The amount invested at Investment B must be less than or equal to $2,250

Step-by-step explanation:

Let

x -----> the amount invested at Investment A yields 5%

y -----> the amount invested at Investment B yields 8%

we know that

x+y=5,000

x=5,000-y  -----> equation A

x \geq 0.25(5,000)

x \geq \$1,250 -----> inequality B

y \leq 0.50(5,000)

y \leq \$2,250 -----> inequality C

x \geq \frac{1}{2}y -----> inequality D

Substitute equation A in the inequality D and solve for y

5,000-y \geq \frac{1}{2}y

Multiply by 2 both sides

10,000-2y \geq y

Multiply by -1 both sides

-10,000+2y \leq -y

Adds y both sides

-10,000+2y+y \leq 0

-10,000+3y \leq 0

adds 10,000 both sides

3y \leq 10,000

Divide by 3 both sides

y \leq \$3,333.33 -----> inequality E

therefore

<em>Solve for y</em>

we have

y \leq \$2,250 -----> inequality C

y \leq \$3,333.33 -----> inequality E

The solution of inequality C and inequality E is

y \leq \$2,250

For y=2,250

x=5,000-y ----> x=5,000-2,250=2,750

so

x \geq \$2,750 -----> inequality F

<em>Solve for x</em>

we have

x \geq \$1,250 -----> inequality B

x \geq \$2,750 -----> inequality F

The solution of inequality B and inequality F is

x \geq \$2,750

therefore

The amount invested at Investment A must be greater than or equal to $2,750

The amount invested at Investment B must be less than or equal to $2,250

7 0
3 years ago
Suppose you want to eat lunch at a popular restaurant. The restaurant does not take reservations, so there is usually a waiting
grin007 [14]

Answer:

a) z_1 =\frac{20-19}{4} =0.25

z_2 =\frac{15-19}{4} =-1

And we can use the complement rule and we got:

P(z>0.25)=1-P(z

P(z>-1)=1-P(z

And replacing we got:

P(X >20| X>15)= \frac{0.401}{0.841}= 0.477

b) z_1 =\frac{20-19}{4} =0.25

z_2 =\frac{18-19}{4} =-0.25

And we can use the complement rule and we got:

P(z>0.25)=1-P(z

P(z>-0.25)=1-P(z

And replacing we got:

P(X >20| X>18)= \frac{0.401}{0.599}= 0.669

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the length of time waiting to be seated of a population, and for this case we know the distribution for X is given by:

X \sim N(19,4.0)  

Where \mu=19 and \sigma=4.0

Part a

For this cae we want to find this probability:

P(X >20| X>15)

And if we use the conditional probability formula we got:

P(X >20| X>15)= \frac{P(X >20 \cap X>15)}{P(X>15)}=\frac{P(X>20)}{P(X>15)}

We can solve the problem using the z score formula given by:

z = \frac{x-\mu}{\sigma}

z_1 =\frac{20-19}{4} =0.25

z_2 =\frac{15-19}{4} =-1

And we can use the complement rule and we got:

P(z>0.25)=1-P(z

P(z>-1)=1-P(z

And replacing we got:

P(X >20| X>15)= \frac{0.401}{0.841}= 0.477

Part b

P(X >20| X>18)= \frac{P(X >20 \cap X>18)}{P(X>18)}=\frac{P(X>20)}{P(X>18)}

We can solve the problem using the z score formula given by:

z = \frac{x-\mu}{\sigma}

z_1 =\frac{20-19}{4} =0.25

z_2 =\frac{18-19}{4} =-0.25

And we can use the complement rule and we got:

P(z>0.25)=1-P(z

P(z>-0.25)=1-P(z

And replacing we got:

P(X >20| X>18)= \frac{0.401}{0.599}= 0.669

5 0
4 years ago
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