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Bess [88]
2 years ago
11

The table shows the amount of milk that Wisconsin dairy farms produced from 1942 to

Mathematics
1 answer:
dangina [55]2 years ago
5 0

Answer:

From the given table, it can be seen, that the amount of milk that Winconsin diary farms produced in 1972 is 7 billion pounds and that the amount of milk that Winconsin diary farms produced in 1997 is 8 billion pounds.

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Jeff drove 249 laps around the racetrack is 9 miles long. how many miles did jeff drive
mr_godi [17]
Hey there Jnorman1287.

Answer:

Distance = 249 x 9
               = 2,241

Hope this helps :D

<em>~Natasha♥</em>
5 0
3 years ago
(Please show step by step workings)
matrenka [14]

Answer:

a. They will need $90,000.00 for the down payment

b. The mortgage amount (principal) will be $360,000.00

c. The monthly principal payment will be $1,500,00

   The monthly interest payment will be $634.40

d. The total interest they will pay: $152,256.00

Step-by-step explanation:

house price= $450,000

down payment = 20%

20-year mortgage

Interest rate= 3.75%

a. How much they will need for the down payment?

The down payment (DoP) is 20% of the house price

DoP= 20% de $450,000

DoP= 0.20*450,000

DoP= $90,000

b. What will be the mortagage amount (the principal)?

The mortgage amount (MoA) (principal) is the difference between the house price and the down payment.

MoA= $450,000 - $90,000

MoA= $360,000

c. How much will their monthly payment be for the principal and interest?

This equation represents the monthly payment (M):

M=P \frac{r(1+r)^{n} }{(1+r)^{n}-1}

where

P= the principal = $360,000

r= monthly interest rate = 3,75% divided by 12 = 0,31%

n= number of payments = 20 years multiplied by 12 months = 240

Let´s input these data into the equation:

M= 360,000\frac{0.0031(1+0.0031)^{240} }{(1+0.0031)^{240} -1}

M= 360,000\frac{0.0031(1.0031)^{240} }{(1.0031)^{240} -1}

Solving the equation:

M= $2,134.40

the principal component of this M would be

$360,000 divided by the 240 months

So, the principal component of M = $1,500.00

And the interest component of M is the difference

$2,134.40 - $1,500.00

So, the interest component of M = $634.40

d. How much total interest will they pay if they take the full 20 years to pay off the mortgage?

With every payment, they will be paying:

$634.40 per month, multiplied by 240 months

The total interest will be $152,256.00

5 0
3 years ago
Which equation represents a linear function? Equation 1: y^3 = 2x +1 Equation 2: y= 3x +1 Equation 3: y= 5x^2 - 1 Equation 4: y=
Yuri [45]
the second equation is linear
8 0
3 years ago
What are the domain and range of f(x) = (1/6)x + 2?
Black_prince [1.1K]
F(x)=x/6+2

There is no restriction upon the values of x, or the values of y.

So the domain and range are both the set of all real numbers.

x=(-oo, +oo) and y=(-oo, +oo)

This can be further seen by the fact that this is a line with a slope of 1/6.  So there is no restriction upon x as all values of x produce real values of y.  And y approaches -oo as x approaches -oo and y approaches +oo as x approaches +oo.
6 0
3 years ago
Please someone help me...​
laiz [17]

Step-by-step explanation:

First factor out the negative sign from the expression and reorder the terms

That's

\frac{1}{ - (( \tan(2A) -  \tan(6A)  )}  -  \frac{1}{ \cot(6A)  -  \cot(2A) }

<u>Using trigonometric </u><u>identities</u>

That's

<h3>\cot(x)  =  \frac{1}{ \tan(x) }</h3>

<u>Rewrite the expression</u>

That's

\frac{1}{ - (( \tan(2A) -  \tan(6A)  )} -    \frac{1}{ \frac{1}{ \tan(6A) } }  -  \frac{1}{ \frac{1}{ \tan(2A) } }

We have

<h3>-  \frac{1}{  \tan(2A) -  \tan(6A)  } -   \frac{1}{ \frac{ \tan(2A) -  \tan(6A)  }{ \tan(6A) \tan(2A)  } }</h3>

<u>Rewrite the second fraction</u>

That's

<h3>-  \frac{1}{  \tan(2A) -  \tan(6A)  } -   \frac{ \tan(6A)  \tan(2A) }{ \tan(2A) -  \tan(6A)  }</h3>

Since they have the same denominator we can write the fraction as

-  \frac{1 +  \tan(6A) \tan(2A)  }{ \tan(2A) -  \tan(6A)  }

Using the identity

<h3>\frac{x}{y}  =  \frac{1}{ \frac{y}{x} }</h3>

<u>Rewrite the expression</u>

We have

<h3>-  \frac{1}{ \frac{ \tan(2A)  -  \tan(6A) }{1 +  \tan(6A) \tan(2A)  } }</h3>

<u>Using the trigonometric identity</u>

<h3>\frac{ \tan(x) -  \tan(y)  }{1 +  \tan(x)  \tan(y) }  =  \tan(x - y)</h3>

<u>Rewrite the expression</u>

That's

<h3>- \frac{1}{ \tan(2A -6A) }</h3>

Which is

<h3>-  \frac{1}{ \tan( - 4A) }</h3>

<u>Using the trigonometric identity</u>

<h3>\frac{1}{ \tan(x) }  =  \cot(x)</h3>

Rewrite the expression

That's

<h3>-  \cot( - 4A)</h3>

<u>Simplify the expression using symmetry of trigonometric functions</u>

That's

<h3>- ( -  \cot(4A) )</h3>

<u>Remove the parenthesis </u>

We have the final answer as

<h2>\cot(4A)</h2>

As proven

Hope this helps you

6 0
3 years ago
Read 2 more answers
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